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- Calculate the pH of a solution prepared by dissolving 0.24 mol of benzoic acid (C7H5O2H) and 0.15 mol of sodium benzoate (NaC7H5O2) in water sufficient to yield 1.00 L of solution. The Ka of benzoic acid is 6.50 × 10-5.Carboxylic acid has acidic functional group (-COOH) and Amine has basic functional group (-NH2). When they are mixed, the resulting structure is charge separation. please explain thisClaculate the pH of a solution prepared by dissolving 0.37 mol of formic acid (HCO2H) and 0.23 mol of sodium formate (NaCO2H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.8 x 10-4.
- The pH of a 0.12 M solution of acetic acid (HCH3CO2) is measured to be 2.83. Calculate the acid dissociation contant Ka of acetic acid.The Ka value for benzoic acid (C6H5COOH) is 6.3×10^−5 and for phenol (C6H5OH) thevalue of Ka is 1.3×10^−10. Which is a stronger base, C6H5COO− (aq) or C6H5O− (aq)?Explain your answer (write reactions to illustrate).The pKa of acetic acid (CH3COOH) is 4.76. If a solution of acetic acid is at a pH of 6.56, the ratio of conjugate base to acid is _____________.
- One step in glucose metabolism involves the conversion of dihydroxyacetone phosphate to glyceraldehyde 3-phosphate by way of an intermediate enediol. Each process involves both a protonation and a depronototation. Dar curved arrows to show the movement of electrons in each step, using HA as an acid for protonotation and B: as a base for deprotonation.At 40 °C, Kw = 2.92 × 10‒14. At 50 °C, a solution with pOH = 7.00, has a pH of ____________. Group of answer choices: 7.00 and is neutral. 7.00 and is slightly basic. 6.53 and is slightly basic. 6.53 and is slightly acidic.The pH and Kh of 0.1N NH4Cl solution, if Kb for NH4OH at 25°C is 1.8x10-5 will be respectively equal to: *
- Acetic acid is weak acid but it gives strongly acidic solution when dissolved in perchloric acid. Explain.You are diligently doing an assignment when a question comes up that had a pH of -1. Is this likely a typo by a tired instructor, or is this number indeed possible? Explain clearly, using an example if need.Calculate the pH at 25°C of a 0.64M solution of anilinium chloride C6H5NH3Cl. Note that aniline C6H5NH2 is a weak base with a pKb of 4.87.