Q4.2. A springboard-type diving board is built from high grade aluminum. This particular board has a mass of 65 kg and is 3.85 m long, 33.8 cm wide, and 5 cm thick. (Aside: Most springboards start thick on one end, then get thinner as it moves to the other end. For this problem, assume the springboard has a constant thickness) One end of the springboard is attached to a hinge. The hinge lets the springboard move up and down, but keeps it from sliding out of place. 1.1 m away from the hinge, the springboard rests on (but is not attached to) a fulcrum. A diver with a mass of 65 kg stands on the far end of the springboard (opposite from the hinge), ready to begin their dive.

Q4.2. A springboard-type diving board is built from high grade aluminum. This particular board has a mass of 65 kg and is 3.85 m long, 33.8 cm wide, and 5 cm thick. (Aside: Most springboards start thick on one end, then get thinner as it moves to the other end. For this problem, assume the springboard has a constant thickness) One end of the springboard is attached to a hinge. The hinge lets the springboard move up and down, but keeps it from sliding out of place. 1.1 m away from the hinge, the springboard rests on (but is not attached to) a fulcrum. A diver with a mass of 65 kg stands on the far end of the springboard (opposite from the hinge), ready to begin their dive.

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter5: Further Applications Of Newton's Laws: Friction, Drag, And Elasticity

Section: Chapter Questions

Problem 42PE: (a) When water freezes, its volume increases by 9.05% (that is, V/V0=9.05102 ). What force per unit...

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At a museum, a 1300-kg model aircraft is hung from a lightweight beam of length 12.0 m that is free to pivot about its base and is supported by a massless cable (Fig. P14.38). Ignore the mass of the beam. a. What is the tension in the section of the cable between the beam and the wall? b. What are the horizontal and vertical forces that the pivot exerts on the beam? FIGURE P14.38 (a) From the free-body diagram, the angle that the string tension makes with the beam is = 55.0 + 18.0 = 73.0, and the perpendicular component of the string tension is FT sin73.0. Summing torques around the base of the rod gives (Eq. 14.2): =0:(12.0m)(1300kg)(9.81m/s2)cos55.0+FT(12.0m)sin73.0=0FT=(12.0m)(1300kg)(9.81m/s2)cos55.0(12.0m)sin73.0FT=7.65103N Figure P14.38ANS (b) Using force balance (Eq. 14.1): Fx=0:FHFTcos18.0=0FH=FTcos18.0=[(12.0m)(1300kg)(9.81m/s2)cos55.0(12.0m)sin73.0]cos18.0=7.27103NFy=0:FVFTsin18.0(1300kg)(9.81m/s2)=0 FV=FTsin18.0+(1300kg)gFV=[(12.0m)(1300kg)(9.81m/s2)cos55.0(12.0m)sin73.0]sin18.0+(1300kg)(9.81m/s2)FV=1.51104N
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