Q5/ The axial force applied on the beam is :equal to 10 kN he100 mm 2m 4m b-50 mm Non of these 10 KN O 20 x 10^6 N.mm 20 Mpa 10 Мра О 2 Мра 10 N/mm^2 40 Mpa 20 N/mm^2 O 2 N/mm^2
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- The beam cross section shown below has been proposed for a short pedestrian bridge. The cross section will consist of two pipes that are welded to a rectangular web plate. Dimensions of the cross section are: h = 430 mm tw = 16 mm d = 110 mm t = 4.8 mm Additionally: • The area of each pipe is A = 1586 mm2. • The moment of inertia of the entire beam cross section about the z centroidal axis is IZ = 194710000 mm4. If the beam will be subjected to a shear force of V = 170 kN, determine the shear stress at point K, located at yK = 70 mm below the z centroidal axis.Engr statics I check it was wrong answer 245.166 I need to show all work. Topic: Shear and Bending Moment A gantry crane of weight W-100 Kg moves across a bridge with the length 1-5 m. The front axle of the crane (which is nearer end A) carries 3/4W whereas the rear axle (nearer end B) carries 1/4 W. The distance of the axles is b = 1/20. Determine the maximum value of the bending moment and enter your answer in N-m units. Remember to also show all your work (FBDs, calculation steps, etc on the handworked file) HINT: Determine the shear and bending moment equationsThe beam safely supports shear forces and bending moments of 2kN and 6.5 kN-m respectively. Based on this criterion, can it be safely subjected to the loads F = 1kN and C = 1.6 kN-m? Use the area method
- The beam safely supports shear forces and bending moments of 2kN and 6.5 kN-m respectively. Based on this criterion, can it be safely subjected to the loads F = 1kN and C = 1.6 kN-m?3) The force, FT = 1 kN, and moment, MT = 0.5 kN-m, at the tip are caused by a wing tip vortexand a winglet, not shown. L = 12 m and the spar has an elastic modulus of E = 70 GPa and aPoisson’s ratio of n = 0.33. The mass of the wing is 4000 kg, and the weight of the engine is 107kN. Use 9.8 m/s 2 for the acceleration due to gravity.Consider the cross-section shown (you can look these up). Pay attention to the coordinate systemgiven in the drawing.d) where is the centroid?e) what is the area?f) Calculate the shear modulus3) The force, FT = 1 kN, and moment, MT = 0.5 kN-m, at the tip are caused by a wing tip vortexand a winglet, not shown. L = 12 m and the spar has an elastic modulus of E = 70 GPa and aPoisson’s ratio of n = 0.33. The mass of the wing is 4000 kg, and the weight of the engine is 107kN. Use 9.8 m/s 2 for the acceleration due to gravity.Consider the cross-section shown (you can look these up). Pay attention to the coordinate systemgiven in the drawing.g) Compute each of these moments of inertia with the values b = 0.4 m, d =0.5 m , t =0.1 m.
- 3) The force, FT = 1 kN, and moment, MT = 0.5 kN-m, at the tip are caused by a wing tip vortexand a winglet, not shown. L = 12 m and the spar has an elastic modulus of E = 70 GPa and aPoisson’s ratio of n = 0.33. The mass of the wing is 4000 kg, and the weight of the engine is 107kN. Use 9.8 m/s 2 for the acceleration due to gravity.Consider the cross-section shown (you can look these up). Pay attention to the coordinate systemgiven in the drawing.a) what is the moment of inertia about y-axis in terms of the symbolic dimensions shown?b) what is the moment of inertia about z-axis in terms of the symbolic dimensions shown?c) what is the polar moment of inertia in terms of the symbolic dimensions shown (i.e.about the x-axis)?d) where is the centroid?e) what is the area?f) Calculate the shear modulusg) Compute each of these moments of inertia with the values b = 0.4 m, d =0.5 m , t =0.1 m.N for Newton, m for meter, mm for millimeter, N/(mm^2) for Stress, mm^2 or m^2 for Area, mm^4 for Moment of inertia and Nm for bending moment. Use brackets if the power is MINUS for Example: 0.00125 N =1.25*10^(-3)N. A beam has a bending moment of 3 kN-m applied to a section with a hollow circular cross-section of external diameter 3.4 cm and internal diameter 2.4 cm . The modulus of elasticity for the material is 210 x 109 N/m2. Calculate the radius of curvature and maximum bending stress. Also, calculate the stress at the point at 0.6 cm from the neutral axis Solution: (i) The moment of inertia = ii) The radius of curvature is (iii) The maximum bending stress is iv) The bending stress at the point 0.6 cm from the neutral axis isA loaded beam, 60 mm wide by 100 mm high and 6 m long, has the shear and moment diagrams as shown below. Determine (a) the magnitude, type and location of the maximum flexural stress (in MPa) (b) the stress (specify the type) in a fiber 30 mm from the top of the beam at a section 3.5 m from the left end. I = bh3/12
- PRIOR ANSWERS: Reaction Forces: By = 76.809 Cy = 15.94 Shear Forces: V (× = 10.5- ft (i.e., just to the left of support B)) = -36.75 kips V ( x = 10.5+ ft (i.e., just to the right of support B)) = 40.059 kips V (x = 25.5 ft) = -12.441 kips V (x = 26.5- ft (i.e.. just to the left of support C))= = -15.941 kips Bending moment: M (x = 10.5 ft (i.e., at support B)) = -192.9375 kips-ft M (x = 25.5 ft) = 14.1975 kips-ftThe proposed shaft is guided in rotation by two roller bearings O and C. T1 = 60 Ib T2 = 400 Ib Reactions: Ro = 293,25 Ib Rc = -178,25 Ib 1) Calculate the torsional stress of the shaft 2) Calculate the bending stress of the shaftCalculate the shaft diameter and torsion angle since the maximum torsional moment is 150 Nm for a 1 meter long shaft with a permissible shear stress of 320 MPa G=80 GPa