QI:A shaft carrying two pulleys I and 2, and supported on two bearings A and B. The shaft transmits a power of 7.5 AW at 360 rpm from the pulley 1 to the pulley 2. The diameters of pulleys1 and 2 are 250 mm and 500 mm respectively. The masses of pulleys 1 and 2 are 10 kg and 30 kg respectively. The belt tensions act vertically downward and the ratio of belt tensions on the tight side to slack side for each pulley is 2.5:1. The shaft is made of plain carbon steel, the Permissible shear stress is 63.333 MPa and the factor of safety is 3. 1- Find the total force acting at the centre line of the pulley I and 2 and 2- Estimate suitable diameter of shaft, Assume G = 79300 MPa. 250 500 250 Px 60 2.3 log = u.e 2n N T (T-T) R (a) T = M² +T = "X 16 2 T4 T1 T2 T3 O----

Elements Of Electromagnetics
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QI:A shaft carrying two pulleys I and 2, and supported on two bearings A and B. The shaft transmits a power of 7.5
W at 360 rpm from the pulley 1 to the pulley 2. The diameters of pulleys ! and 2 are 250 mm and 500 mm
respectively. The masses of pulleys 1 and 2 are 10 kg and 30 kg respectively. The belt tensions act vertically
downward and the ratio of belt tensions on the tight side to slack side for each pulley is 2.5:1. The shaft is made of
plain carbon steel, the Permissible shear stress is 63.333 MPa and the factor of safety is 3.
1- Find the total force acting at the centre line of the pulley 1 and 2 and
2- Estimate suitable diameter of shaft, Assume G = 79300 MPa.
250
500
250
Px 60
2.3 log
T
= u.e
%3D
2n N
T (T-T) RC
1.
(a)
B.
T, = JM? + T =xtx d
=--X TX
16
T4 T1 T2 T3
Transcribed Image Text:QI:A shaft carrying two pulleys I and 2, and supported on two bearings A and B. The shaft transmits a power of 7.5 W at 360 rpm from the pulley 1 to the pulley 2. The diameters of pulleys ! and 2 are 250 mm and 500 mm respectively. The masses of pulleys 1 and 2 are 10 kg and 30 kg respectively. The belt tensions act vertically downward and the ratio of belt tensions on the tight side to slack side for each pulley is 2.5:1. The shaft is made of plain carbon steel, the Permissible shear stress is 63.333 MPa and the factor of safety is 3. 1- Find the total force acting at the centre line of the pulley 1 and 2 and 2- Estimate suitable diameter of shaft, Assume G = 79300 MPa. 250 500 250 Px 60 2.3 log T = u.e %3D 2n N T (T-T) RC 1. (a) B. T, = JM? + T =xtx d =--X TX 16 T4 T1 T2 T3
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