QUESTION 1 Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a. T2 m Applying Newton's second law on the rightmost block: EFx= = ma Applying Newton's second law on the block at the center: EFx= -T2 D Applying Newton's second law on the leftmost block: EFx= = ma If each block has a mass of 10 kg and is accelerating at 2 m/s-, the magnitude of the tension on the second string is T2= N.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter5: The Laws Of Motion
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QUESTION 1
Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on
the rightmost block as shown in the figure below so that each block moves to right with acceleration a.
T2
T1
Applying Newton's second law on the rightmost block:
EFx =
= ma
Applying Newton's second law on the block at the center:
EFx =
- T2 =
Applying Newton's second law on the leftmost block:
IFx=
= ma
If each block has a mass of 10 kg and is accelerating at 2 m/s-, the magnitude of the tension on the second string is Ty =
N.
QUESTION 2
Transcribed Image Text:Question Completion Status: QUESTION 1 Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a. T2 T1 Applying Newton's second law on the rightmost block: EFx = = ma Applying Newton's second law on the block at the center: EFx = - T2 = Applying Newton's second law on the leftmost block: IFx= = ma If each block has a mass of 10 kg and is accelerating at 2 m/s-, the magnitude of the tension on the second string is Ty = N. QUESTION 2
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