Question 10 of 13 1. Show complete solution for determining the Molarity of NaOH (use trial 1 only) 2. Calculate the average molarity of NaOH for trial 1 and 2. Answer with text and/or attachments: H E E I I I BI U s x x 工田 Paragraph RobotoLightNew 12pt E - A - A fx 2 1. [1.2075g KHP (1M KHP/204.22g/mol KHP)] / [24.3mL (1L/1000mL)] = 0.243 2. (Trial 1's Mol NAOH + Trial 2's Mol NaOH) / 2 = 0.2425M

Question 10 of 13 1. Show complete solution for determining the Molarity of NaOH (use trial 1 only) 2. Calculate the average molarity of NaOH for trial 1 and 2. Answer with text and/or attachments: H E E I I I BI U s x x 工田 Paragraph RobotoLightNew 12pt E - A - A fx 2 1. [1.2075g KHP (1M KHP/204.22g/mol KHP)] / [24.3mL (1L/1000mL)] = 0.243 2. (Trial 1's Mol NAOH + Trial 2's Mol NaOH) / 2 = 0.2425M

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.18QAP

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