Question 13 The Zener breakdown occurs at moderate voltages because of tunneling of charge carriers in the heavily doped p-n diodes. (а) True (b) False
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help with multiple choice
The Zener breakdown takes place because of a high electric field. Whenever the high electric-field is applied across the PN junction diode, then the electrons start flowing through the PN-junction. It increases the reverse current and then it leads to breakdown of the diode.
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- 1)Define Drift and Diffusion current in Semiconductor. 2. Why n - type impurities are called as Donor impurities? 3. Give the other names of depletion region? (At least Two) 4. General Purpose Diodes are mostly preferred in chopper circuits. Is it True? Justify.Sketch current I vs, voltage V for the circuits below. The breakdown voltage of the Zener diodes are shown. Assume 0.6V for all diodes (including Zener diodes) in the forward bias region.Determine Q-point for the diodes in the circuit given below using the ideal diode model where, R1 = 12.2 kΩ, R2 = 16 kΩ, and R3 = 14 kΩ. (Note: Label the diodes from left to right.)
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- Draw the V-I characteristic curve of a Ge based Zener diode with Zener breakdown voltage (?z=5 ?). Indicate three different regions of the curve. Subject: Electronic devicesAssuming the practical model, what PIV rating is required for the diode? The transformer is specified to have a 12 Vrms secondary voltage for the standard 110 V across the primary. (2nd Approximation)Ideally, we want the voltage for a Zener diode to be constant in the breakdown region. What does this imply about the dynamic resistance in the breakdown region for an ideal Zener diode?
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