Question 14: A probability distribution has equal mean and median, and P(88 < X < 96) = 0.68, P(84< X <100) = 0.95, P(80< X <104) = 0.997. Part A: How would you classify this distribution? Why? Part B: Determine the mean and standard deviation of this distribution. Part C: Calculate and sketch the following situation: P(64< X <110). Part D: Calculate and sketch the following situation: P(X < c) = 0.1998

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Question 14:
A probability distribution has equal mean and median, and P(88 < X < 96) = 0.68, P(84< X <100) = 0.95,
P(80< X <104) = 0.997.
Part A: How would you classify this distribution? Why?
Part B: Determine the mean and standard deviation of this distribution.
Part C: Calculate and sketch the following situation: P(64< X <110).
Part D: Calculate and sketch the following situation: P(X < c) = 0.1998
Transcribed Image Text:Question 14: A probability distribution has equal mean and median, and P(88 < X < 96) = 0.68, P(84< X <100) = 0.95, P(80< X <104) = 0.997. Part A: How would you classify this distribution? Why? Part B: Determine the mean and standard deviation of this distribution. Part C: Calculate and sketch the following situation: P(64< X <110). Part D: Calculate and sketch the following situation: P(X < c) = 0.1998
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