Question 15: You run a regression analysis on a bivariate set of data (n=79n=79). You obtain the regression equationy=3.362x−24.355y=3.362x-24.355with a correlation coefficient of r=0.725r=0.725 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 10 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.) You run a regression analysis on a bivariate set of data (n = 79). You obtain the regression equationy = 3.362x24.355with a correlation coefficient of r = 0.725 (which is significant at a = 0.01). You want to predict whatvalue (on average) for the explanatory variable will give you a value of 10 on the response variable.What is the predicted explanatory value?X =(Report answer accurate to one decimal place.)

To find: What is the predicted explanatory value? x = __??

Question 15: You run a regression analysis on a bivariate set of data (n=79n=79). You obtain the regression equationy=3.362x−24.355y=3.362x-24.355with a correlation coefficient of r=0.725r=0.725 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 10 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.)

Question 15: You run a regression analysis on a bivariate set of data (n=79n=79). You obtain the regression equationy=3.362x−24.355y=3.362x-24.355with a correlation coefficient of r=0.725r=0.725 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 10 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter4: Equations Of Linear Functions

Section4.5: Correlation And Causation

Problem 2AGP

See similar textbooks

Similar questions

Special Rounding Instructions For this exercise set, round all regression parameters to three decimal places, but round all other answers to two decimal places unless otherwise indicated. First Down The following table shows the probability P, as a percentage, of a college football team converting on fourth down when not goal to go versus the distance D, in yards, to the first down maker. 28 D = distance, in yards P = probability 1 70 2 60 3 53 4 46 5 41 6 37 7 34 8 32 a.Use exponential regression to model the data. b.Plot the data along with the exponential model. c.What probability does the model give of gaining a first down for fourth down and 10yards to go? Note: the actual probability is 28.
Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s pole vault height has fallen below the value predicted by the regression line in Example 2. This might have occurred because when the pole vault was a new event there was much room for improvement in vaulters’ performances, whereas now even the best training can produce only incremental advances. Let’s see whether concentrating on more recent results gives a better predictor of future records. (a) Use the data in Table 2 (page 176) to complete the table of winning pole vault heights shown in the margin. (Note that we are using x=0 to correspond to the year 1972, where this restricted data set begins.) (b) Find the regression line for the data in part ‚(a). (c) Plot the data and the regression line on the same axes. Does the regression line seem to provide a good model for the data? (d) What does the regression line predict as the winning pole vault height for the 2012 Olympics? Compare this predicted value to the actual 2012 winning height of 5.97 m, as described on page 177. Has this new regression line provided a better prediction than the line in Example 2?
What does the y -intercept on the graph of a logistic equation correspond to for a population modeled by that equation?
In a study of possible correlation between the height in cm (X) and the weight in kg (Y) of chimpanzees, a sample of 40 animals produces a correlation coefficient of r=0.813 and a regression line with equation Y=0.34X+19.5. What is the expected weight of a chimpanzee that is 157 cm tall? Round off final answer to 2 decimal places.
You run a regression analysis on a bivariate set of data (n=82n=82). With ¯x=50.7 and ¯y=65.7, you obtain the regression equation y=4.309x − 152.766 with a correlation coefficient of r = 0.134. You want to predict what value (on average) for the response variable will be obtained from a value of x = 100 as the explanatory variable.What is the predicted response value? y = (Report answer accurate to one decimal place.)
The Pearson correlation between X1 and Y is r = 0.40. When a second variable, X2, is added to the regression equation, we obtain R2 = 0.64. How much variance for the Y scores is predicted by using both X1 and X2 as predictor variables? 0.40 or 40% 0.64 or 64% 0.48 or 48% 0.16 or 16%
In a linear regression model, calculate the slope of the line, b1, when the correlation coefficient is r = -0.37, and the standard deviations of the predictor variable equals sx = 0.552 and the standard deviation of the response variable equals sy = 0.552. Only round your final answer to 2 decimal places.
The average midterm score in a large statistics class was 70 with an SD of 10. The average final score in the same class was 65 with an SD of 15. The correlation coefficient between midterm and final scores was r=0.6. Using the regression line, we predict the final score of a student with a midterm score of 60 to be , but this prediction is likely to be off by about . Fill in the blanks, rounding each answer to one decimal point.
A set of n = 15 pairs of X and Y values has a correlation of r = +0.80 with SSY = 75, and the regression equation for predicting Y is computed. Find the standard error of estimate for the regression equation. How big would the standard error be if the sample size were n = 30.
If a sample of 25 pairs of data yields a correlation coefficient, r, of 0.390 and the scatterplot displays a linear trend, can you use the regression equation to make predictions, assuming your x-values are within the domain of the data set? Choose your answer from the multiple choice answers below A.) Yes, because rcrit = 0.396 and the regression coefficient, r, is less than this value. B.) Yes, because rcrit = 0.381 and the regression coefficient, r, is greater than this value. C.) No, because rcrit = 0.381 and the regression coefficient, r, is greater than this value. D.) No, because rcrit = 0.396 and the regression coefficient, r, is less than this value.
After performing a statistical regression on a set of data the value of the correlation coefficient r was -0.2041. What does that imply about the data?