Would the change in your overall end product change any data points you were given? Question 2Draw all intermediates and the final product for the following reaction. Label all spectral data for the product.1. Br2, heat2. NaNH2, NH3C3H8CSH83. HBr, peroxides4. O:=ASpectral DataSpectral DataMS: 44 m/z (molecular ion)IR (cm'): 2800-3000CNMR(ppm)/DEPT: 16/pos,15/negHNMR(ppm): 1.34, 2H, m; 0.90,6H, tMS: 68 m/z (molecular ion)IR (cm1): 3307 (strong), 2876-2968, 2120CNMR (ppm)/DEPT: 84.6/pos, 68/none,22/neg, 20.4/neg, 13.4/posHNMR: 2.17, 2H, t; 1.94, 1H, s; 1.56, 2H,sextet; 1.00, 3H, t

Answered: Image /qna-images/answer/a2253ffc-0315-414c-8c76-56a847dc1af2.jpg

Question 2 Draw all intermediates and the final product for the following reaction. Label all spectral data for the product. 1. Br2, heat 2. NaNH2, NH3 C3H8 C5H8 3. HBr, peroxides 4. O:= Spectral Data Spectral Data MS: 44 m/z (molecular ion) IR (cm): 2800-3000 CNMR(ppm)/DEPT: 16/pos, 15/neg HNMR(ppm): 1.34, 2H, m; 0.90, 6H, t MS: 68 m/z (molecular ion) IR (cm'): 3307 (strong), 2876-2968, 2120 CNMR (ppm)/DEPT: 84.6/pos, 68/none, 22/neg, 20.4/neg, 13.4/pos HNMR: 2.17, 2H, t; 1.94, 1H, s; 1.56, 2H, sextet; 1.00, 3H, t

Question 2 Draw all intermediates and the final product for the following reaction. Label all spectral data for the product. 1. Br2, heat 2. NaNH2, NH3 C3H8 C5H8 3. HBr, peroxides 4. O:= Spectral Data Spectral Data MS: 44 m/z (molecular ion) IR (cm): 2800-3000 CNMR(ppm)/DEPT: 16/pos, 15/neg HNMR(ppm): 1.34, 2H, m; 0.90, 6H, t MS: 68 m/z (molecular ion) IR (cm'): 3307 (strong), 2876-2968, 2120 CNMR (ppm)/DEPT: 84.6/pos, 68/none, 22/neg, 20.4/neg, 13.4/pos HNMR: 2.17, 2H, t; 1.94, 1H, s; 1.56, 2H, sextet; 1.00, 3H, t

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter19: Eas: Electrophilic Aromatic Substitution

Section: Chapter Questions

Problem 45E

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