Question 26: resting body temperatures are normally distributed with an average of 98.25 degrees Fahrenheit and a standard deviation of 0.73 degrees Fahrenheit. What is the probability a random patient examined by a nurse will have a body temperature greater than 99 degrees Fahrenheit? Round to the hundredths. Resting body temperatures are normally distributed with anaverage of 98.25 degrees Fahrenheit and a standard deviationof 0.73 degrees Fahrenheit. What is the probability a randompatient examined by a nurse will have a body temperaturegreater than 99 degrees Fahrenheit? (Round to the hundredths)0.15O 0.85O 96.55O 99.94

Answered: Question 26: resting body temperatures…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 26: resting body temperatures are normally distributed with an average of 98.25 degrees Fahrenheit and a standard deviation of 0.73 degrees Fahrenheit. What is the probability a random patient examined by a nurse will have a body temperature greater than 99 degrees Fahrenheit? Round to the hundredths.

Resting body temperatures are normally distributed with an
average of 98.25 degrees Fahrenheit and a standard deviation
of 0.73 degrees Fahrenheit. What is the probability a random
patient examined by a nurse will have a body temperature
greater than 99 degrees Fahrenheit? (Round to the hundredths)
0.15
O 0.85
O 96.55
O 99.94

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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