Question
Asked Feb 26, 2019
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Question 3

part a: Calculate the molarity of 0.650 mol of glucose in 0.400 L of a glucose solution.

part b: Calculate the molarity of 68.0 g of HCl in 3.00 L of an HCl solution.

part c: Calculate the molarity of 28.0 g of NaOH in 330. mL of an NaOH solution.

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Expert Answer

Step 1

(a)

Moles of glucose = 0.650mol

Volume of glucose = 0.400L

The molarity of glucose solution is calculated as,

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Step 2

(b)

Mass of HCl = 68.0g

Volume of HCl = 3.0L

The moles of HCl is calculated using its molar mass as,

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Step 3

The molarity of HCl solutio...

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