Question 30 Given: Pd2+ + Cd2+ Cd (s) +Pd4+ - E' cell = +0.323 V What is the potential of this cell reaction at 298 K when [Pd2+] = 0.150 M. [Pd4+] = 2.00 x 10-3 M. [Cd2+] = 0.200 M? +0.358 V O +0.308 V O +0.288 V O +0.328 O 0.00 V

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
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Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.19QAP
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Question 30
Given:
Pd2+ + Cd2+ Cd (s) +Pd4+
1
E' cell = +0.323 V
What is the potential of this cell reaction at 298 K when [Pd2+] = 0.150 M. [Pd4+] = 2.00 x 10-3 M. [Cd2+] = 0.200 M?
+0.358 V
+0.308 V
O +0.288 V
O +0.328
O 0.00 V
Transcribed Image Text:Question 30 Given: Pd2+ + Cd2+ Cd (s) +Pd4+ 1 E' cell = +0.323 V What is the potential of this cell reaction at 298 K when [Pd2+] = 0.150 M. [Pd4+] = 2.00 x 10-3 M. [Cd2+] = 0.200 M? +0.358 V +0.308 V O +0.288 V O +0.328 O 0.00 V
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