Question 4Find the vertex and the focus of the following parabola: x2 -4y-4 = 0V: (0,1) F: (0, -2)V: (0,1) F: (0, -1)V: (0, -1) F: (0,0)V: (0, -1) F: (0,2) Question 8Given: (x2-2)2/4 + (y-4)2/16= 1Where can you find one of the vertices?(0,4)(-2,4)(2,4)(2,0)

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Answered: Question 4 Find the vertex and the…

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter7: Conic Sections

Section7.1: Parabolas

Problem 3E: The graph of the equation y2=4px is a parabola with focus F(__, __) and directrix x = ____. So the...

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Similar questions

By definition, a hyperbola is the locus of points whose positive difference of distances from two fixed points F1 and F2 called foci is constant. In the grid provided, find points whose difference of distances from points F15, 0 and F2-5, 0 is 6. That is, locate some points for which PF1-PF2=6 or PF2-PF1=6; point P3, 0 is one such point. Then sketch the hyperbola.
The graph of the equation y2=4px is a parabola with focus F(__, __) and directrix x = ____. So the graph of y2=12x is a parabola with focus F(__, __) and directrix x = ____.

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Question 4 Find the vertex and the focus of the following parabola: x2 -4y-4 = 0 V: (0,1) F: (0, -2) V: (0,1) F: (0, -1) V: (0, -1) F: (0,0) V: (0, -1) F: (0,2) Question 8 Given: (x2-2)2/4 + (y-4)2/16= 1 Where can you find one of the vertices? (0,4) (-2,4) (2,4) (2,0)