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Question 4 THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AH = -81.9 kJ AH = -159.1 kj AX (g) + ½R2 (g) → XAR (g) Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) AH = -510.4 kJ Round your answer to 1 decimal place.

Question 4 THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AH = -81.9 kJ AH = -159.1 kj AX (g) + ½R2 (g) → XAR (g) Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) AH = -510.4 kJ Round your answer to 1 decimal place.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.146QP: Given the following (hypothetical) thermochemical equations:...
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Question 4 THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AH = -81.9 kJ AX (g) + ½R2 (g) → XAR (g) AH = -159.1 kJ Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) AH = -510.4 kJ Round your answer to 1 decimal place.
Transcribed Image Text:Question 4 THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AH = -81.9 kJ AX (g) + ½R2 (g) → XAR (g) AH = -159.1 kJ Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) AH = -510.4 kJ Round your answer to 1 decimal place.
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