Question 4. The switch in the figure is closed at t = 0. The initial voltage of the capacitor is 30 V. Find a) ve (t) for t≥ 0. b) i(t) for t≥ 0. c) i(t) for t≥ 0. d) [₂(t) for t≥ 0. + vc(1) 0.5 µF t=0 30 V REQ 10 kQ2 i(t) i₁(t) 20 ΚΩ i₂(1) 20 ΚΩ
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- In the circuit of the figure, the switch S has been in position a for a long time; when the current through the inductor is maximum, the switch changes to position b (this instant is taken as t = 0). If the current source is iS(t) = 2.1213 cos (100πt + π/ 4). Determine: i) the value of R2 so that at t = 4 mS the current iL (t = 4mS) = 1 A. ii) The expression for the inductor current iL(t) t> 0 iii) the value of iL(t) at t = 0. iv) the expression of the inductor voltage vL(t) t> 0. v) the value of vL(0).1) The circuit shown below is initially, for t < 0, with capacitor C connected to a battery (Vbat = 12 V).The key is switched at t = 0, disconnecting the battery and turning on the capacitor to the rest of the circuit.a)Calculate the circuit current in the time domain, i(t).b) In practice, after how long can the energy stored in the circuit be considered to be irrelevant (close to zero)?The triangular voltage pulse shown below is applied to a 200 mF capacitor. a) Write the expressions thatdescribe vc(t) in the five time intervals t < 0, 0 ≤ t ≤ 2 , 2 ≤ t ≤ 6, 6 ≤ t ≤ 8, and t > 8. b) Derive theexpressions for the capacitor current, power, and energy for the time intervals in part (a).
- Given the circuit below with the switch closed for a long time, then opening at t=0, and with the values R1=193KΩ, R2=186KΩ, R3=107KΩ, calculate the capacitor voltage at t =0.Please answer ASAP and I'll upvote, thank you. In the given circuit, switch S1 is in position A and switch S2 is open. Both switches are in these states for a very long time. At t=0, switch S1 moves from position A to B while switch S2remains open. 10ms after switch S1 moves to position B, switch S2 is closed and remains closed for 20ms only. Determine the expressions for the inductor current for 0≤t<10ms, 10ms≤t<30ms, 30ms≤t<∞, and determine the time (in ms) after switch S1 moves to position B is the current in the inductor equivalent to 30% of the initial value (at ?=0).In the circuit shown, the switch is inthe closed position for a long timebefore it opens at time ? = 0.A. Find the differentialequation satisfied by the outputvoltage, v0(t) for t> 0. B. the initial conditions for this circuit are: v0(0+) = 0 and dv0/dt(0+) =−30,000 V/s. .findv0(t) for t > 0.
- An electric circuit contains a 1-H inductor, a 4-$ resistor, and a voltage source of sin t. The resulting differential equation relating the current i and the time t is di / dt + 4i = sin t. Find i after 0.5 s by Euler's method with At= 0.1 s if the initial current is zero. Solve the equation exactly and compare the values. Use Euler's method to find i after 0.5 s. iapprox = A Round the final answer to four decimal places as needed. Round all intermediate values to nine decimal places as needed.)The current in and the voltage across a 5 H inductor are known to be zero for t≤0. The voltage across the inductor is given by the graph shown for t≥0. 1. Derive the expression for the current as a function of time in the intervals 0≤t≤1 s, 1 s≤t≤3 s, 3 s≤t≤5 s, 5 s≤t≤6 s, and 6 s≤t<∞. 2. For t>0, what is the current in the inductor when the voltage is zero? 3. Sketch i versus t for 0≤t<∞.The two switches in the circuit shown in Figure operate synchronously. When switch 1 is in position a, switch 2 is closed. When switch 1 is in position b, switch 2 is open. Switch 1 has been in position a for a long period of time. At t = 0, it moves instantaneously to position b. Determine vc(t) for t ≥ 0.
- The circuit shown is at steady state before the switch closes. The inductor currents are both zero before the switch closes (i1(0) = i2(0) = 0). The voltage across the 2H-inductor is 4e-5t V for t > 0, otherwise 0V for t < 0. (a) Determine the inductor currents i1(t) and i2(t) for t ≥ 0. (b) Determine the energy stored by each inductor 200ms after the switch closes. (c) In the equivalent inductor (for the parallel inductors) determine the (i) current and the (ii) energy stored for 200 ms after the switch closes. Answer: 0.4(1 − e−5t) A, 0.1(1 − e−5t) A, 16.0mJ, 63.9mJ, 316mA, 79.9mJIn the circuit shown, the switch is open, and the capacitors are uncharged. At t=0, the switch S is closed. Find the equivalent resistance of the circuit at t=0. R1=2R, R2=R, C1=C, C2=2C.The current i(t) in an RL circuit is governed by the differential equation di/dt + R/L i = 1/L (E(t)), where R and L are constants and E(t) represents the applied EMF. At t = 0, the switch in the circuit isclosed, and the applied EMF increases linearly from 0 V to 10 V in a time interval of 5 seconds. The EMF thenremainsconstantfort ≥5.Determinethecurrent in the circuit for t ≥0.