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QUESTION 5 (10 blanks) If the gravitational potential energy of the water is equal to the increase in the internal energy of the water, compute the change in its temperature (in Kelvin), if water drops from a height of 50 m. Assume no work is done on/by the water (C = 4184 J/kg K) Sol. Using the first law of thermodynamics: A U=Q - Since W = Then A U=Q But, by virtue of the problem, the internal energy is equal to AU = While Q = ΔΤ Then h= ΔΤ AT = K (2 decimal place)

QUESTION 5 (10 blanks) If the gravitational potential energy of the water is equal to the increase in the internal energy of the water, compute the change in its temperature (in Kelvin), if water drops from a height of 50 m. Assume no work is done on/by the water (C = 4184 J/kg K) Sol. Using the first law of thermodynamics: A U=Q - Since W = Then A U=Q But, by virtue of the problem, the internal energy is equal to AU = While Q = ΔΤ Then h= ΔΤ AT = K (2 decimal place)

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.62QE: A 50-mL solution of a dilute AgNO3 solution is added to 100 mL of a base solution in a coffee-cup...
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QUESTION 5 (10 blanks) If the gravitational potential energy of the water is equal to the increase in the internal energy of the water, compute the change in its temperature (in Kelvin), if water drops from a height of 50 m. Assume no work is done on/by the water (C = 4184 J/kg K) Sol. Using the first law of thermodynamics: A U=Q - Since W = Then AU=Q But, by virtue of the problem, the internal energy is equal to AU = While Q = AT Then h= ΔΤ AT = K (2 decimal place)
Transcribed Image Text:QUESTION 5 (10 blanks) If the gravitational potential energy of the water is equal to the increase in the internal energy of the water, compute the change in its temperature (in Kelvin), if water drops from a height of 50 m. Assume no work is done on/by the water (C = 4184 J/kg K) Sol. Using the first law of thermodynamics: A U=Q - Since W = Then AU=Q But, by virtue of the problem, the internal energy is equal to AU = While Q = AT Then h= ΔΤ AT = K (2 decimal place)
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