QUESTION 5 Suppose an electron (q = – e= - 1.6 × 10¬19 C,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the inal speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U Since K = mv² and using the formula for potential energy above, we arrive at an equation for speed: v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s v=

Q: A small sphere has a charge of q = 5e, where e is the charge on an electron. (a) Determine the…

A: a) Given data The magnitude of the charge on the sphere is given as q = 5e. The distance of the…

Q: Part 1: A proton is accelerated from rest through a potential difference of 25599 V. What is the…

A: The kinetic energy of the proton , when it gets accelerated by a potential V=25599 V is calculated…

Q: LL THE 3 BLANKS) Suppose an electron (,) is accelerated from rest through a potential difference of…

A: formula for potential energy U U=eV U=-1.6×10-19×5000 U=-8×10-16 J (answer)

Q: Particle A has a charge of –10µC and a mass of 0.001kg. Particle A starts in a position where the…

A: Given Data Charge of particle A is qA=-10 μC=-10×10-6 C Mass of the particle is m=0.001 kg Potential…

Q: QUESTION 5 Suppose an electron (q = – e= - 1.6× 10¬19 C,m=9.1 × 10¬31 kg) is accelerated from rest…

A: The Relation between the Potential energy U and potential difference Vab  Is given as: U=Vab (e)…

Q: An electron is accelerated horizontally from rest in a television picture tube by a potential…

A: The y-component acceleration of the electron between the plates can be found as, Acceleration,…

Q: Through what potential difference would an electron need to be accelerated for it to achieve a speed…

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Q: 3. An electron enters a parallel plate apparatus 10.0 cm long and 2.0 cm wide, moving horizontally…

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Q: apart. They are then Brought together, with a fiHal Separauon UI 3.3 IIII. How much work does it…

A: Electric potential energy is given as U=qV                                                .......(1)…

Q: 1a. If an electron is accelerated in an accelerator possessing a potential difference of 40 MV, what…

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Q: A mass has a charge of q = 5e, where e is the charge on an electron. (a) Determine the electric…

A: according to guidelines, first 3 sub parts are answered here.   in this question  we simply  get…

Q: Problem 4: A point charge Q1 =+5.2 µC is fixed in space, while a point charge Q2 =+2.7 nC, with mass…

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Q: . What is its speed at point B

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Q: A mass has a charge of q = 5e, where e is the charge on an electron. (a) Determine the electric…

A: Electrical potential at a distance 'r' for charge '+q' is                                V =…

Q: Compute for the electric potential from a source charge of 8.88 x 10^(-11) C if a test charge will…

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Q: An electron is to be accelerated from a velocity of 3.50×10° m/s to a velocity of 8.00 10° m/s.…

A: Part A. Mass of electron = m=9.1×10-31 Kg Charge on electron = q=1.6×10-19 C Initial velocity = u =…

Q: A stationary proton is moved from point A, where the potential is 450 V, to    point B, where the…

A: (a) work done by the electric force We=eVA-VB=1.6×10-19 C450 V-125 V=5.2×10-17 J

Q: An electron that is initially 53 cm away from a proton is displaced to another point. If the change…

A: Given: Initial distance ri=53 cm, Change in electric potential energy ∆PE=3×10-28J. Required: Final…

Q: Q3. Point charge q₁ = 2.0 nC is located at (0, 0). a) What is the electric potential at point A (2.0…

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Q: Suppose an electron (q = - e= -1.6× 10¬19 c,m=9.1×10¬31 kg) is accelerated from rest through a…

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Q: 1. V E (a) Calculate is the change in PE when an electron moves through an electric field, E = 50…

A: PE change = q(E×d) PE change = -1.6 × 10-19 (50×6) PE change = -4.8 × 10-17 J (a) The mechanical…

Q: If an electron travels 0.200 m from an electron gun to a TV screen in 36.3 ns, what voltage was used…

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Q: Suppose an electron (q = – e= -1.6 × 10¬19 c,m=9.1 × 10¬31 kg) is accelerated from rest through a…

A: The potential energy of electron is  U = - e V  U = - 1.6×10-19×5000 = - 8 ×10-16 J

Q: Problem 6: Find the potential energy of the 10 µC charge at the origin. Electric Potential of the…

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Q: An electron is accelerated from rest by a potential difference. If we increase the potential by a…

A: KE = eV0 KE will increase 9 times.  Potential energy will increase 9 times. KE=12mv2 v will be three…

Q: 2. How much work must we do on an electron to move it from point A, which is at a potential of +50V,…

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Q: 1. An electric dipole consists of point charges, q1 = +12 nC and q2 = -12 nC placed 10.0 cm apart.…

A: Givenq1 = +12 nC = +12 ×10-9 Cq2 = -12 nC = -12 ×10-9 C

Q: (a) Find the potential difference AV, required to

A: Part A:

Q: 1. An electron in the picture tube of an old television set is accelerated from rest through a…

A: Given value--- Potential difference = 5000 V. We have to find--- a. What is the change in…

Q: A spherical conductor has a radius of 8 mm and a charge of 20μC. Calculate the electric potential at…

A: Given that, q=20μC=20×10−6CR=8 mm=8×10−3m For conductor potential at surface is equal to potential…

Q: 5) The electric potential of a solid insulating sphere of radius R with electric charge Q is…

A: Electric field is the negative gradient of potential. We can use this fact to find electric field

Q: . An electron is accelerated from rest through a potential difference of 15V. What is the change in…

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Q: Suppose an electron (q = - e= - 1.6× 10¬19C,m=9.1×10¬3' kg) is accelerated from rest through a…

A: Given data:  charge of an electron, q =-e =-1.6×10-19C  Mass of an electron, m ==9.1×10-31 kg…

Q: 1. In the following diagram, Q1 = -2.50 µC and Q2 = 6.00 µC. They are 1.50 meters apart. Determine a…

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Q: Two point charges q1 = +26µC and q2 = −17.5µC are 64 cm apart. a. What is the potential energy of…

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Q: QUESTION 1 Suppose an electron (q= -e= - 1.6 x 10-19 C.m=9.1 x 10-31 kg) is accelerated from rest…

A: As it is a multiple question, I answer the first question. Please resubmit the second question…

Q: Suppose an electron (g = - e = -1.6x 10-19 C.m=9.1 x 10-31 kg) is accelerated from rest through a…

A: Charge, q = -1.6×10-19 CMass, m = 9.1×10-31 kgPotential difference, Vab = 5000 V

Q: A point charge Q1=+5.9 uC is fixed in space, while a point charge Q2=+2.2 nC, with mass 7.6 ug, is…

A: (a) The potential energy of the system is     2.78 x 10-4 J (b) Speed is 5.76 m/s

Q: Activity 2 A small particle has charge - 5. 00 uC and mass 2.00 x 10 kg. It moves from point A,…

A: charge (q) = -5 μC mass (m) = 2×10-4 kg VA = +200 volts VB = +800 volts speed of particle at A = 5…

Q: Calculate the electrical potential at a point 12 cm from the center of a properly charged disc with…

A: Radius of disc R = 5 cm Distance at which potential is to be calculated x = 12 cm surface charge…

Q: Find the electric potential at x=3 m if the electric potential at x=0 is -120 V. 2. What is the…

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Q: Suppose an electron (q = -e= -1.6 × 10' 'C,m=9.1 × 10¯³ª kg) is accelerated from rest through a…

A: Potential energy = Charge * Potential difference U = q Vab  q = -e , Hence,  U = - e × Vab  K = - U…

Q: Two charges were placed on the x-axis as shown in the y (m) side figure. a) Determine the point in…

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Q: potential difference is needed to stop an electron

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Q: What potential difference is needed to stop an electron that has an initial velocity v=1.88x10^7…

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