QUESTION 5 Suppose an electron (q = – e= - 1.6× 10¬19 C,m=9.1 × 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K+U=0 K= -U

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 11P: An electron is at the origin, (a) Calculate the electric potential VA at point A, x = 0.250 cm. (b)...
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Please fill in the blanks. Suppose an electron (q equals -e equals -1.6 x10^-19 C, m=9.1x10^-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:

QUESTION 5
Suppose an electron (q = - e= -1.6× 10¬19 C,m=9.1× 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the
final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U = 0
K= -U
Since K =
mv and using the formula for potential energy above, we arrive at an equation for speed:
v= (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=
Transcribed Image Text:QUESTION 5 Suppose an electron (q = - e= -1.6× 10¬19 C,m=9.1× 10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K= -U Since K = mv and using the formula for potential energy above, we arrive at an equation for speed: v= ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=
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