Question 6 6.1 Calculate the enthalpy of the reaction 2NO (g) + O2(g)-2NO: (g), given the following reactions and enthalpies of formation: (i) 12 N₂(g) + O₂-NO: (g) (ii) 12 N₂(g) +120: (g) → NO(g) ΔΗ = 33.2 kJ ΔΗ = 90.2 kJ 6.2 The standard enthalpy of formation of NH3(g) at 298 K is equal to -462.11 kJ mol¹. Using the heat capacity data given below (valid for the temperature range of 298 K to 1600 K). Cpm (H₂) / J. K¹ mol¹ = 29.07-0.837 x 10³ +2.012 x 10 Cp.² (N₂) / J. K'¹ mol'¹ = 26.98 +5.192 x 10³-0.3376 x 10 C. (NH)/J.K¹ mol¹ = 25.89 +32.58 x 10³-3.046 x 10 Calculate the standard molar heat of formation of NH3 (g) at 900 K (in kJ.mol), at 1000 K. Give your final answer to 3 significant figures.

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Chapter22: Organic And Biological Molecules
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Problem 158CP: Estimate H for the following reactions using bond energies given in Table 8.5. 3CH2=CH2(g) + 3H2(g) ...
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Question 6
6.1 Calculate the enthalpy of the reaction 2NO (g) + O2(g) →2NO₂ (g), given the following
reactions and enthalpies of formation:
(i) 12 N₂(g) + O: NO: (g)
(ii) 12 N₂(g) +1202(g) → NO(g)
ΔΗ = 33.2 kJ
ΔΗ = 90.2 kJ
6.2 The standard enthalpy of formation of NH3 (g) at 298 K is equal to -462.11 kJ mol¹. Using
the heat capacity data given below (valid for the temperature range of 298 K to 1600 K).
Cp.m" (H₂)/J. K¹ mol¹ = 29.07-0.837 x 10³
Cp, mº (N2) / J. K¹ mol¹ = 26.98 +5.192 x 103
Cp, anº (NH3)/J.K¹ mol¹ = 25.89 +32.58 x 10³-3.046 x 106
K²
+2.012 x 106
K²
-0.3376 x 106
Calculate the standard molar heat of formation of NH3 (g) at 900 K (in kJ.mol), at 1000 K. Give
your final answer to 3 significant figures.
Transcribed Image Text:Question 6 6.1 Calculate the enthalpy of the reaction 2NO (g) + O2(g) →2NO₂ (g), given the following reactions and enthalpies of formation: (i) 12 N₂(g) + O: NO: (g) (ii) 12 N₂(g) +1202(g) → NO(g) ΔΗ = 33.2 kJ ΔΗ = 90.2 kJ 6.2 The standard enthalpy of formation of NH3 (g) at 298 K is equal to -462.11 kJ mol¹. Using the heat capacity data given below (valid for the temperature range of 298 K to 1600 K). Cp.m" (H₂)/J. K¹ mol¹ = 29.07-0.837 x 10³ Cp, mº (N2) / J. K¹ mol¹ = 26.98 +5.192 x 103 Cp, anº (NH3)/J.K¹ mol¹ = 25.89 +32.58 x 10³-3.046 x 106 K² +2.012 x 106 K² -0.3376 x 106 Calculate the standard molar heat of formation of NH3 (g) at 900 K (in kJ.mol), at 1000 K. Give your final answer to 3 significant figures.
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