SpecimenMethod 1Method 211.52124571.538596721.55149271.535489531.47488651.473753741.54406241.552924151.53815551.529729761.65057171.608116871.32619341.323154481.50384771.511096291.4281791.4512758101.4674651.4845284111.54721261.5571789121.29185781.3506767131.46184781.4986059141.59366011.5668332151.48033331.5175659161.62906381.6226015171.44276611.4122777181.67964921.6888483191.40450121.400003201.34893281.3604714211.50581521.5016116221.47209911.4776931231.45459041.509409241.4305781.4316958251.51691061.5382421261.5364951.5902854271.61758561.64074281.34555971.4092455291.44306941.4113823301.54383351.5427199 QUESTION 6Problem 2b:Two different methods can be used to measure the impurity level in steel alloys. 30 specimens are measured using both methods, and the results arelogged in the Excel file Final_P2_Data.xlsx.b) Provide a 95% confidence interval for the standard deviation of the impurity level as measured with Method 2. Assume that the test results arenormally distributed. Report the upper limit of the confidence interval with 3 decimals

Given Data with standard deviation : Specimen Method 2 1 1.5385967 2 1.5354895 3 1.4737537…

Answered: QUESTION 6 Problem 2b: Two different…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data. Also, conduct a hypothesis, with alpha = 0.05, test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. Construct a 95% confidence interval Which of the following correctly displays the standard error? 0.0046 0.009 0.001 0.00002 0.008
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A 30 month study is conducted to determine the difference in rates of accidents per month between two departments in an assembly plant. If a sample of 12 from the first department averaged 12.3 accidents per month with a standard deviation of 3.5, and a sample of 9 from the second department averaged 7.6 accidents per month with standard deviation of 3.4, find: The 95% confidence interval between the difference in rates between the two departments (round off to four decimal places) is: A. [2.9782; 6.4218] B. [1.5083; 7.8917] C. [2.9782; 7.8917] D. [1.5083; 6.4218] E. None of the preceding

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Specimen	Method 1	Method 2
1	1.5212457	1.5385967
2	1.5514927	1.5354895
3	1.4748865	1.4737537
4	1.5440624	1.5529241
5	1.5381555	1.5297297
6	1.6505717	1.6081168
7	1.3261934	1.3231544
8	1.5038477	1.5110962
9	1.428179	1.4512758
10	1.467465	1.4845284
11	1.5472126	1.5571789
12	1.2918578	1.3506767
13	1.4618478	1.4986059
14	1.5936601	1.5668332
15	1.4803333	1.5175659
16	1.6290638	1.6226015
17	1.4427661	1.4122777
18	1.6796492	1.6888483
19	1.4045012	1.400003
20	1.3489328	1.3604714
21	1.5058152	1.5016116
22	1.4720991	1.4776931
23	1.4545904	1.509409
24	1.430578	1.4316958
25	1.5169106	1.5382421
26	1.536495	1.5902854
27	1.6175856	1.64074
28	1.3455597	1.4092455
29	1.4430694	1.4113823
30	1.5438335	1.5427199