Question 8 Consider the following IVP: x" - 4x' + 4x = 4e2t; x(0) = -1, x'(0) = -4 Find the general solution. A 22" (1?-21+ 1) x(t) = = -e2(13– 212+1) B x(t) 4 © x(t) = e" (212– 21 – 1) D x(t) = e'(212 –t-2) %3D

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