QUESTION 8 In the previous question, M were calculated for 20% HCI, fill in the formula below to determine how much HCI is needed to prepare 100ml of 0.1M of HCI. C1V1 = C2V2 M.V1 = M.L V1 = L HCI (5 decimal places) V1 = ml HCI (2 decimal places)
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- Calculate the molarity of 78.0 mL of 0.350 M NaOH diluted to 0.250 L with water. Answer in M, not in scientific notation.Concentration Units. Follow the format. Given: Formula: Calculations and answer: 6. lf you dissolve 0.70 HCl moles in enough water to prepare 250ml, what is the molarity and normality of the solution you preparedQUESTION 10 Calculate the resultant Molarity ( M ) when 2.50 L of water is added to 500.0 mL of 12 M NaoH solution?
- How many mL of 0.146 M NaC2H3O2 are needed to supply 15.7 g NaC23O2 ? Answer in mLQUESTION 40 A salt solution was made by combining 45g of NaCl with 125g of water. What is the percent concentration (m/m) of the NaCl solution? 26% 36% 3.78% 2.78%Dr. A wants to dilute 30.0 mL of 2.60 M H2SO4 to a new concentration of 0.700 M. To what volume (in mL) should she dilute the H2SO4 solution?
- Solute: H2SO4 Composition of Solution: mole% H2SO4 = 40 % Density, g/mL: 20 degrees: 1.681 ; 80 degrees: 1.625 Find: 1. g solute per 100 mL of solution at 80 degrees 2. g solute per 1000 mL of solution at 20 degrees 3. ppm of soluteWhat volume of water is required to make a 0.09 M MgCl2 solution staring with 0.33 g of MgCl2. Report your answer to the nearest milliliter.Concentration Units. Follow the format. Given: Formula: Calculations and answer: 9. How much 0.075 M NaCl solution can be made by diluting 450ml of 9.0 M NaCl?
- 2 What concentration in molarity is made by diluting 244 mL of 10.0 M HCl to 1.67 L? Answer with Sig FigsCalculate the molarity of 78.0 mL of 0.350 M NaOH diluted to 0.250 L with water. Answer in M.TOPIC: Stoichiometric Calculations 1.) How can 2L of 35mM NaOH be prepared? (Sodium hydroxide has a molecular weight of 40). 2.) How many moles of NaCl are present in 350mL of a 2M solution? 3.) How many millimoles of NaCl are present in 75mL of a 0.025M solution?