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- For each of the graphs you drew in 2.1 please determine its adjacency matrix and adjacency list. Discuss whether you think one representation is more advantageous than the other.Three components are connected to form a system as shown in the accompanying diagram. Because the components in the 2–3 subsystem are connected in parallel, that subsystem will function if at least one of the two individual components functions. For the entire system to function, component 1 must function and so must the 2–3 subsystem. The experiment consists of determining the condition of each component [S (success) for a functioning component and F (failure) for a nonfunctioning component]. (Enter your answers in set notation. Enter EMPTY or ∅ for the empty set.) There us a graph shown in the pictures. Questions are posted on the pictures too.http://1.bp.blogspot.com/-_oz7NidtZUw/VT9p-cTflFI/AAAAAAAAAbQ/osdMcO15L-w/s1600/ncr%2Bmap1.jpg Construct a graph from this map where the vertices are the cities and are connected by an edge if the cities share boundaries. Determine the least number of colors needed to re-color the map such that no two areas that share boundaries have the same color.
- Three components are connected to form a system asshown in the accompanying diagram. Because the componentsin the 2–3 subsystem are connected in parallel, thatsubsystem will function if at least one of the two individualcomponents functions. For the entire system to function,component 1 must function and so must the 2–3 subsystem. The experiment consists of determining the condition ofeach component [S (success) for a functioning componentand F (failure) for a nonfunctioning component].a. Which outcomes are contained in the event A thatexactly two out of the three components function?b. Which outcomes are contained in the event B that atleast two of the components function?c. Which outcomes are contained in the event C that thesystem functions?d. List outcomes in C9, A ø C, A ù C, B ø C, andB ù C.A Hamiltonian path in a network is a closed path thatpasses exactly once through each node in the network before returning to its starting point. Taking a four-city TSP as anexample, explain why solving a TSP is equivalent to findingthe shortest Hamiltonian path in a network.Three components are connected to form a system as shown in the accompanying diagram. Because the components in the 2–3 subsystem are connected in parallel, that subsystem will function if at least one of the two individual components functions. For the entire system to function, component 1 must function and so must the 2–3 subsystem. (View Pic) The experiment consists of determining the condition of each component [S (success) for a functioning component and F (failure) for a nonfunctioning component]. (Enter your answers in set notation. Enter EMPTY or ∅ for the empty set.) (a) Which outcomes are contained in the event A that exactly two of the three components function?A = ? (b) Which outcomes are contained in the event B that at least two of the components function?B = ? (c) Which outcomes are contained in the event C that the system functions?C = ? (d) List outcomes in C'.C' = ? List outcomes in A ∪ C.A ∪ C = ? List outcomes in A ∩ C.A ∩ C = ? List outcomes in B ∪ C.B ∪ C = ?…
- A large family travelling on the road in convoy decided to stop at a bed and breakfast since it was getting pretty late. However, there were too many people so they decided to split up to 3 nearby bed and breakfasts. 40% of the family members stayed at B&B 1, 35% stayed at B&B 2, and 25% stayed at B&B 3. According to feedback, 6% of the rooms in B&B 1 have lights that do not work, 9% of rooms in B&B 2 have lights that do not work, and 7% of rooms in B&B 3 have lights that do not work. 1) Given the data above, make a venn diagram.2) Determine the probability that a family member will have a room with functional lights. 3) Determine the probability that a family member whose room lights do not work was assigned to B&B A.The dependencies between the 10 activities listed in the table above are as follows:• The project starts with two activities—A, and B—which can be done concurrently.• When activity A is finished, activity C can start• When activity B is finished, activities D and E can start• When both activities C and D are finished, activity F can start• When activity E is finished, activity G can start• When activity F is finished, activity H can start• When both activities G and H are finished, activity I can start• When activity G is finished, activity J can start• The project is complete when activities I and J are finished Questions1. Organize the information above in an activity precedence table showing the activity, precedent and duration (calculated using the PERT weighted average formula and round to the nearest integer).2. Draw an AON network diagram and calculate its early start, early finish, late start and late finish times, floats (Free and total) for each activity. Make sure you…find the hamiltonian circuit