QUESTION If the speed of the boat relative to the water is increased, what happens to the angle? O e remains the same. O e increases. O e decreases.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 40P
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GOAL Solve a simple two-dimensional relative motion problem.
VRE
VBE
VBR
W-OE
PROBLEM The boat in the figure is heading due north as it crosses a wide river with a velocity of 10.0
km/h relative to the water. The river has a uniform velocity of 5.00 km/h due east. Determine the velocity
of the boat with respect to an observer on the riverbank.
STRATEGY Again, we look for key phrases. "The boat. . . (has) a velocity of 10.0 km/h relative to the
water" gives v BP: "The river has a uniform velocity of 5.00 km/h due east" gives vRE because this implies
velocity with respect to Earth. The observer on the riverbank is in a reference frame at rest with respect to
Earth. Because we're looking for the velocity of the boat with respect to that observer, this last velocity is
designated veE: Take east to be the +x-direction, north the +y-direction.
SOLUTION
Arrange the three quantities into the
proper relative velocity equation.
VBR =VBE - VRE
%3D
Write the velocity vectors in terms of
their components. For convenience,
these are organized in the following
x-component
(km/h)
y-component
(km/h)
Vector
10.0
BR
table.
V BE
5.00
Transcribed Image Text:GOAL Solve a simple two-dimensional relative motion problem. VRE VBE VBR W-OE PROBLEM The boat in the figure is heading due north as it crosses a wide river with a velocity of 10.0 km/h relative to the water. The river has a uniform velocity of 5.00 km/h due east. Determine the velocity of the boat with respect to an observer on the riverbank. STRATEGY Again, we look for key phrases. "The boat. . . (has) a velocity of 10.0 km/h relative to the water" gives v BP: "The river has a uniform velocity of 5.00 km/h due east" gives vRE because this implies velocity with respect to Earth. The observer on the riverbank is in a reference frame at rest with respect to Earth. Because we're looking for the velocity of the boat with respect to that observer, this last velocity is designated veE: Take east to be the +x-direction, north the +y-direction. SOLUTION Arrange the three quantities into the proper relative velocity equation. VBR =VBE - VRE %3D Write the velocity vectors in terms of their components. For convenience, these are organized in the following x-component (km/h) y-component (km/h) Vector 10.0 BR table. V BE 5.00
E Apps M Gmail
Find the x-component of velocity.
0 = v,- 5.00 km/h v = 5.00 km/h
Find the y-component of velocity.
10.0 km/h =
= 10.00 km/h
- 0 >
Find the magnitude of VBE'
2.
VBE
%3D
V (5.00 km/h)2 + (10.0 km/h)2
= 11.2 km/h
%3D
Find the direction of VBE
5.00 m/s'
10.0 m/s.
e = tan
= tan
= 26.6°
LEARN MORE
REMARKS The boat travels at a speed of 11.2 km/h in the direction 26.6 east of north with respect to
Earth.
QUESTION If the speed of the boat relative to the water is increased, what happens to the angle?
O e remains the same.
O e increases.
O e decreases.
PRACTICE IT
Use the worked example above to help you solve this problem. The boat in the figure is heading due north
as it crosses a wide river with a velocity of 15.0 km/h relative to the water. The river has a uniform
velocity of 4.30 km/h due east. Determine the velocity of the boat with respect to an observer on the
riverbank.
magnitude
km/h
direction
° east of north
EXERCISE
HINTS:
GETTING STARTED | I'M STUCK!
Suppose the river is flowing east at 2.80 m/s and the boat is traveling south at 3.90 m/s with respect to
the river. Find the speed and direction of the boat relative to Earth.
speed
m/s
direction
O south of east
Search for anything
Transcribed Image Text:E Apps M Gmail Find the x-component of velocity. 0 = v,- 5.00 km/h v = 5.00 km/h Find the y-component of velocity. 10.0 km/h = = 10.00 km/h - 0 > Find the magnitude of VBE' 2. VBE %3D V (5.00 km/h)2 + (10.0 km/h)2 = 11.2 km/h %3D Find the direction of VBE 5.00 m/s' 10.0 m/s. e = tan = tan = 26.6° LEARN MORE REMARKS The boat travels at a speed of 11.2 km/h in the direction 26.6 east of north with respect to Earth. QUESTION If the speed of the boat relative to the water is increased, what happens to the angle? O e remains the same. O e increases. O e decreases. PRACTICE IT Use the worked example above to help you solve this problem. The boat in the figure is heading due north as it crosses a wide river with a velocity of 15.0 km/h relative to the water. The river has a uniform velocity of 4.30 km/h due east. Determine the velocity of the boat with respect to an observer on the riverbank. magnitude km/h direction ° east of north EXERCISE HINTS: GETTING STARTED | I'M STUCK! Suppose the river is flowing east at 2.80 m/s and the boat is traveling south at 3.90 m/s with respect to the river. Find the speed and direction of the boat relative to Earth. speed m/s direction O south of east Search for anything
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