Question part 3: What is E[Y]? Assume that a > 1. L triel

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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1
Let X - Beta(a, B) and Y =
Beta distribution pdf:
fx (x) = cx"-1(1 – x)³-1 for x € (0, 1) and parameters a > 0, B > 0,
Γ (α + β)
where c is a normalizing constant equal to
Г(а)Г(8)
(Recall that I'(z + 1) = zT(z) = z(z – 1)r(z – 1) =...)
Question part 3:
What is EY? Assume that a > 1.
hint: again, use the kernel trick.
a + B
a – B
a + B
1
1
1
-1
+B
a + B
We do not have enough information to answer this question.
Transcribed Image Text:1 Let X - Beta(a, B) and Y = Beta distribution pdf: fx (x) = cx"-1(1 – x)³-1 for x € (0, 1) and parameters a > 0, B > 0, Γ (α + β) where c is a normalizing constant equal to Г(а)Г(8) (Recall that I'(z + 1) = zT(z) = z(z – 1)r(z – 1) =...) Question part 3: What is EY? Assume that a > 1. hint: again, use the kernel trick. a + B a – B a + B 1 1 1 -1 +B a + B We do not have enough information to answer this question.
1
Let X - Beta(a, B) and Y =
Beta distribution pdf:
fx (x) = cx"-1(1 – x)B-1 for x E (0, 1) and parameters a > 0, B > 0,
T(a + B)
where c is a normalizing constant equal to
I(a)r(8)
Recall that I'(z + 1) = zT(z) = z(z – 1)T(z – 1) =
=...
Question part 1:
E X = . What is E[X²]?
a+B*
hint: using the kernel trick (figuring out a new normalizing constant) will probably be
faster than looking up the variance and doing the necessary algebra. Consolidate your
x terms and recognize the new Beta distribution's parameters to figure out its
normalizing constant.
aß
(a + B)2 (a + B+ 1)
a?
(a+ B)2
We do not have enough information to answer this question.
(a +1)a
(a +B+1)(a + B)
Transcribed Image Text:1 Let X - Beta(a, B) and Y = Beta distribution pdf: fx (x) = cx"-1(1 – x)B-1 for x E (0, 1) and parameters a > 0, B > 0, T(a + B) where c is a normalizing constant equal to I(a)r(8) Recall that I'(z + 1) = zT(z) = z(z – 1)T(z – 1) = =... Question part 1: E X = . What is E[X²]? a+B* hint: using the kernel trick (figuring out a new normalizing constant) will probably be faster than looking up the variance and doing the necessary algebra. Consolidate your x terms and recognize the new Beta distribution's parameters to figure out its normalizing constant. aß (a + B)2 (a + B+ 1) a? (a+ B)2 We do not have enough information to answer this question. (a +1)a (a +B+1)(a + B)
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