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- Give one advantage of the proposed HPLC identification test over the current UV-Visible Spectroscopy method of Amiloride Hydrochloride.Explain difference between 1) Allowed Transition and Forbidden Transition 2) Transmittance and Absorbance 3) Chromophore and Auxochrome 4) Absorption Maximum and Molar Absorptivity 5) Bathochromic effect and Hyperchromic effectHaylee was very rushed and still needed the mp of her pure microscale unknown. She filled hercapillary tube with the proper amount of sample and placed it in the apparatus. She quickly ran themp and was dismayed when not only did the observed mp cover a 6°C range, but was also higher thanexpected. Explain what she did wrong.
- The ppm concentration of Pb2+ in a blood sample were measured with Spectrophotometry. 5.00 mL of a blood sample were taken and this sample gave a signal of 0.301 a.u.. Another 5.00 mL of a blood sample were mixed with 0.50 mL og 1.75 ppm Pb2+. Then, this mixture was diluted to 25.00 mL and this diluted mixture gave a signal of 0.406 a.u.. What is the ppm concentration of a blood sample?similarities and differences of the IR Reports. Include peaks and functional groups/ fingerprint regions.Which detector is suitable for compounds which do not absorb energy in the uv-vis region? a. UV-Vis detector b. IR detector c. Photodiode array detector
- Record your absorbance data for the YELLOW and RED dyes below. Calculate the dye concentration in mM for each cuvette using M1V2 = M2v2 . Remember the concentration of stock solutions (100^ % dye) is 0.020 mM(mM= millimolar =mm /L). Data for YELLOW: peak absorbance used on spectrophotometer =420nm Cuvette 1 - 100% dye = 0.680 absorption Cuvette 2 - 75% dye = 0.510 absorption Cuvette 3 - 50% dye = 0.340 absorption Cuvette 4 - 25% dye = 0.170 absorption Data for RED - peak absorption used on spectrophotometer = 500nm Cuvette 1 - 100% dye: 0.621 absorption Cuvette 2 - 75%: 0.466 absorption Cuvette 3 - 50% dye: 0.311 absorption Cuvette 4 - 25% dye: 0.1555 absorptionIn determining the concentration of a sample X, it was found that it has maximum absorbance at 275 nm. Compound X, has molar absorptivity at 275 nm of 8400 L / mol.cm. Using a spectrophotometer with a 1 cm cuvette, an absorbance of 0.70 was found. What is the concentration of compound X in the sample?Caffeine was analyzed using UV-Vis spectroscopy. The average absorbance for 10 blanks is 0.01826. The standard deviation from the measurement is 0.00101. The slope of the calibration curve is 1.75 × 109 M−1. Calculate the signal detection limit, concentration detection limit and limit of quantification.
- Monomer-dimer formation can affect the absorbance measurements using Beer’s law, it is an example of: A. chemical deviation B. instrumental deviation C. real deviation D. instrumental deviationUV-Visible spectroscopy is used to determine the content of an analyte in a capsule. Weigh 100.0 mg of the capsule contents (total weight of contents 500 mg), add 2.0 mL of 0.05 M NaOH, filter the flask, and make up to 25.00 mL with NaOH. The measured transmittance of this solution is 33.0%. The analyte standard is prepared by dissolving 10.0 mg of standard in 25.00 mL of 0.05 M NaOH, then taking 10.00 mL of that solution and diluting to a final volume of 50.00 mL where the transmittance is obtained from 44.0%. Calculate the content of the analyte in the capsule.An over-the-counter (OTC) drug product needs to be analyzed to determine if it is adulterated. The product is a complex mixture of ingredients that have a wide range of solubilities. The active ingredient is non-volatile and has a λmax at 280 nm and emits light at 360 nm. The other ingredients in the product absorb light at 280 nm but do not emit light. Select the most appropriate analysis technique based on the information provided. a) fluorescence spectroscopy b) absorbance spectroscopy c) HPLC with absorbance detection d) HPLC with fluorescence detection