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- Practice Pedigree Problem help. I am confused so please show. Label Phenotypes and genotypes as you go about the Pedigree (and whatever else might be required)! Thank you again for your help, these questions confuse me). Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individuals which are heterozygous for these alleles are calico or tortiseshell in color. a). If a long-haired, black male is mated with a calico female homozygous for short hair, what kind of kittens will be produced in the F1generation? Give both genotypes and phenotypes; express the genotypes both symbolically and in words.PEDIGREE ANALYSIS ANSWER THE FOLLOWING QUESTIONS 1. The pedigree below shows a family's pedigree for colorblindness. Which sex can be carriers of colorblindness and not have it? 2. With this in mind, what kind of trait is colorblindness? 3. Why dies individual IV-7 have colorblindness? 4. Why do all the daughters in generation II carry the colorblind gene? 5. Name two (2) IV generation colorblind males.Punnet square problems A=Codominant; B=Codominant; O=Recessive Mary is homozygous for type A blood. Steve is homozygous for type O blood. If they have children, what are the possible phenotypes and genotypes of their children, and what is the probability of each? Mary and Steve have a son, Brad. Brad’s wife, Samantha is heterozygous for type B blood. If they have children, what are the possible phenotypes and genotypes of their children, and what is the probability of each? Stella loves roses and decides to cross her red rose with her white rose. All of the resulting offspring of this cross are pink roses. What can you say about the red and white alleles as a result of this cross? Stella decides to cross two of the pink roses. What are the possible genotypes and phenotypes of the offspring and the probabilities of each? DNA replication, Transcription and Translation problems It is S phase of the cell cycle, and time to replicate the cell’s DNA. Using the following strand of DNA…
- Background Information: Autosomal Dominant/Recessive- The trait is encoded by a single genetic locus with two segregating alleles: One dominant (A) and one recessive (a). The locus is not on a sex chromosome, and is not linked to any other trait unless specified.Autosomal Codominance- This mode is the same as Autosomal Dominant/Recessive, except that neither allele isdominant or recessive and heterozygous individuals have a distinct phenotype. X-linked Dominant/Recessive - The trait is encoded by a single genetic locus with two segregating alleles: One dominant (A) and one recessive (a). The locus is located on the X-chromosome, and is not linked to any other trait unless specified.X-linked Codominance- This is the same as X-linked dominant/recessive, except that heterozygous females (twocopies of the X-chromosome) experience a distinct phenotype relative to females that are homozygous for either of the two alleles. Males will be segregating with two phenotypes (because they only have…Hi, I'm having trouble with my study guide for my upcoming genetics exam. If someone could please help with work shown and an explanation it would help so much! Thank you!! 2a. The pedigree below represents inheritance of rare condition. What pattern of inheritance is most consistent with the data? Assign alleles to all individuals to support your answer. If an allele is unknown, assign it a ? symbol. NOTE: Individuals whose phenotype or genotype cannot be determined are assumed to be unaffected and homozygous, unless otherwise indicated. 2b. In addition to the alleles you’ve indicated, describe 2 overall features of the pedigree that make it consistent with your chosen form of inheritance. 2c. Based on your mode of inheritance, what is the probability that the child of couple IV-4 x IV-5 will be affected? Show your work. attached is the pedigreeCould someone please help me with this grade 11 bio dihybrid cross problem in detail and how to solve this question, using a strategy? Assume that curly hair (C) is dominant to straight hair. Albinism (P ) is recessive to normal skin pigmentation. A woman who is heterozygous for curly hair and albinism has a child. The father is homozygous dominant for curly hair and has albinism. (a) Determine the possible phenotypes for their child. (double-crossing, Puneet square)(b) Calculate the four different probabilities of a child beingboth a male and of each phenotype.(c) What is the probability that the child will expressalbinism and have curly hair like his father?
- polygenic trait mating 2 An AaBBCcdd male mates with an AaBbCCDD female. 1. What is the maximum number of ridge-producing genes possible in one of the children? 2. What would be the TRC for this child if it is a male? 3. What is the minimum number of ridge-producing genes possible in a child of this couple? 4. If this child were a female, would she have a higher or lower TRC than the parent with the lower ridge count? A. lower B. higher C. equalMODIFIED TRUE OR FALSE. In the following items, read each statement carefully. I. The Mendelian pattern of inheritance is a general term that refers to any pattern of inheritance in which traits do not segregate in accordance with Mendel’s lawsII. As an example, a characteristic may be controlled by one gene with two alleles, but the two alleles have a same relationship like the simple dominant-recessive relationship a. The first statement (I) is correct and the second statement (II) is wrong b. The first statement (I) is wrong and the second statement (II) is correct c. Both statements are correct d. Both statements are wrong MODIFIED TRUE OR FALSE. In the following items, read each statement carefully. I. The continuity of life from one cell to another has its foundation in the reproduction of cells by way of the cell cycle.II. The cell cycle is an orderly sequence of events in the life of a cell from the division of a single parent cell to produce…Instruction - Please answer them correctly - Please answer all of them, they are connected. PEDIGREE ANALYSIS and SYMBOLOGY Examine the pedigree which has X linked Dominant inheritance of disorder. Use letter X* (asterisk denotes disorder) as genotype of the individuals which can be XX, XY, X*X*, X*X and X*Y. a. What is the genotype of IV-6? b. What is the genotype of III-6? c. What is the genotype of II-3? d. What is the genotype of III-8? e. If couple I-1 and I-2 will have a son, what is the probability of having the disorder? f. If couple III-8 and III-9 will have another child, what is the probability of having the disorder? g. Theoretically, if individual IV-3 and individual IV-5 will marry and will have a child, what is the probability of having a child without the X-linked disorder?
- Help me create a pedigree of this information: Pedigree analysis: Generation 1: Normal parents (AA x AA) Generation 2: Carrier parents (AA x AS) Generation 3: Affected child (AS x AS) Generation 4: Affected grandchild (SS) This pedigree has two normal parents in the first generation. Second generation carriers carry the sickle cell trait from one parent. The disease is 25% more likely to be inherited in the third generation if both parents have the 'S' allele. If both parents have the 'S' allele, their children will have sickle cell anemia in the fourth generation1-Gigantism is being traced in a family through a pedigree. Its mode of inheritance is thought to be autosomal recessive. You examine the pedigree and decide that the mode of inheritance is not correct. What is the correct mode of inheritance? 2-Provide 2 pieces of evidence for the mode of inheritance selected for Gigantism. (i.e.- Individual 45 is afflicted and passed it on to all of her offspring, indicating that it is dominant. Or there is a gendered pattern of inheritance seen when Individual 99 passed it on to only his female offspring.)A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?