R= 22 R= 10e %3D R=22 Ro- 24 ke 4a %3D loor Rz 2e A SOLUE FOR (2PTS) Stow YOUR SOWTONS: 1 RponAL - 2. ITOTAL - Is - 7 Is - 8. I7- 9. I lo - b Vq - 3. Ragaol- 4. R3456789011 5 R12345C78AP Il- 14 V7 | 1o. Ill - K Vio NOTE: PLEASE MAKE YOUR ANr IN ORDER.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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please make the answer in order and complete solution.
please answer only from 6-15
1. 7.41 Ω
2. 13.495 A
3. 3 Ω
4. 3.41 Ω
5. 7.41 Ω

R=22
R= 10e
Ro- 2a
Re 4a
%3D
loor
Rz 2e
A SOLUE FOR (2PTS) SHaw YOUR OUTUNS:
V -
Is -
7 Is -
8. I7-
9. I to -
L RTOTAL-
6.
2. ITOTAL -
12 Va
I3 Va
3. R7ga10||-
4- R34567890-
14 Vz
lo. In -
5 R12345C789AID II-
K Vio
NOTE: PLEASE MAKE YOUR AN IN ORDER.
/114
Transcribed Image Text:R=22 R= 10e Ro- 2a Re 4a %3D loor Rz 2e A SOLUE FOR (2PTS) SHaw YOUR OUTUNS: V - Is - 7 Is - 8. I7- 9. I to - L RTOTAL- 6. 2. ITOTAL - 12 Va I3 Va 3. R7ga10||- 4- R34567890- 14 Vz lo. In - 5 R12345C789AID II- K Vio NOTE: PLEASE MAKE YOUR AN IN ORDER. /114
SAMPLE PROBLEM SOURCE:
PLE.
lov
k sak
REURU TL
ceke FR V
1,53A
R- 20.0
Inon- 152A
V. - 30.6V
Ra= 209
= Zaa +204 2an+50-652
Vz Ink2 (1.6)(20)
In Iases 1,53A
V1= 30.6V
(coE CURRET ne ET
I153A
* 1.A
PETRN T TAE ORIGINA ORCU IT
V= 30-C
Ir =0.36rA
Vag - Vy - Vg = 7GSV
( VILTRCE PR EALLE Vr 7G5V
-0.0S A
V, - 36CV
R4
V= V, + Va +V,+ Var
Is- Vs
0.76FA
765 V
Se. I + Iç : 153A
SPME
%3D
Transcribed Image Text:SAMPLE PROBLEM SOURCE: PLE. lov k sak REURU TL ceke FR V 1,53A R- 20.0 Inon- 152A V. - 30.6V Ra= 209 = Zaa +204 2an+50-652 Vz Ink2 (1.6)(20) In Iases 1,53A V1= 30.6V (coE CURRET ne ET I153A * 1.A PETRN T TAE ORIGINA ORCU IT V= 30-C Ir =0.36rA Vag - Vy - Vg = 7GSV ( VILTRCE PR EALLE Vr 7G5V -0.0S A V, - 36CV R4 V= V, + Va +V,+ Var Is- Vs 0.76FA 765 V Se. I + Iç : 153A SPME %3D
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