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From part (b) of the given image, FAD is in – x direction. This means current along AD is the same direction as the wire. Therefore, current is clock-wise. From part (c), FBC is along +x direction.
The net force is the difference between FAD and FBC. Magnitude of FAD is greater than the magnitude of FBC. Therefore, the net force will also be in – x direction towards the wire. Hence, the net force is attractive.
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