R1 R2 15 V lov R4 R3 The loop on the left has current I, and the loop on the right has current Iz. Let R1 = 1, R2 = 3, R3=8, R4=9. Build the system of linear equations for this circuit. Then, choose the correct system of linear equations from the options below. O 101 – 912 = 1O - 91 + 2012 = 15 O 101 - 912 = -10 9I +2012 15 O 1011 – 91, = -10 - 91 + 2012 = 15 %3D O 1011 + 91, = 10 91 + 2012 = 15 %3D O 1011 + 912 = -10 91 +2012 = 15

Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter32: Inductance
Section: Chapter Questions
Problem 32.56P: Show that Equation 32.28 in the text Ls Kirchhoffs loop rule as applied to the circuit in Figure...
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R1
R2
15 V
lov
R4
R3
The loop on the left has current I, and the loop on the right has current Iz.
Let R1 = 1, R2 = 3, R3=8, R4=9. Build the system of linear equations for this circuit. Then, choose
the correct system of linear equations from the options below.
O 101 – 912 = 1O
- 91 + 2012 = 15
O 101 - 912 = -10
9I +2012
15
%3D
O 101 - 912 = -10
- 91 + 2012 = 15
O 1011 + 91, = 10
91 + 2012 = 15
%3D
O 1011 + 912 = -10
91 +2012 = 15
||
Transcribed Image Text:R1 R2 15 V lov R4 R3 The loop on the left has current I, and the loop on the right has current Iz. Let R1 = 1, R2 = 3, R3=8, R4=9. Build the system of linear equations for this circuit. Then, choose the correct system of linear equations from the options below. O 101 – 912 = 1O - 91 + 2012 = 15 O 101 - 912 = -10 9I +2012 15 %3D O 101 - 912 = -10 - 91 + 2012 = 15 O 1011 + 91, = 10 91 + 2012 = 15 %3D O 1011 + 912 = -10 91 +2012 = 15 ||
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