The 226Ra nucleus undergoes alpha decay according to Equation 43.12. (A) Calculate the Q value for this process. The masses are 226.025 408 u for 226Ra, 222.017 576 u for 222Rn, and 4.002 603 u for 4/2He. (B) What is the kinetic energy of the alpha particle after the decay? Ra → Rn + He(43.12)8886

(a) Write the formula for the energy released in the process.

Answered: Ra → Rn + He (43.12) 88 86

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter25: Electromagnetic Induction

Section: Chapter Questions

Problem 4STP

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The ²²⁶Ra nucleus undergoes alpha decay according to Equation 43.12. (A) Calculate the Q value for this process. The masses are 226.025 408 u for ²²⁶Ra, 222.017 576 u for ²²²Rn, and 4.002 603 u for 4/2He. (B) What is the kinetic energy of the alpha particle after the decay?

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