Rainfall Evaluation: Cumulative Cumulative Time (hr) Time (hr) Rainfall (mm) Rainfall (mm) 1 5.95 13 147.075 2 16.525 14 148.525 3 30.3 15 152.625 4 49.4 16 158.525 68.625 17 163.875 90.575 18 170.4 105.1 19 179.45 106.05 20 194.225 9 117.575 21 210.95 10 131.175 22 231.35 11 141.675 23 243.6 12 146.525 24 250 Transform this cumulative rainfall series from a local rain gauge into an incremental rainfall hyetograph. If this fell over a watershed with an area of 1 hectare, what was the volume of rainfall (m3) distributed over the watershed? 67 00

Rainfall Evaluation: Cumulative Cumulative Time (hr) Time (hr) Rainfall (mm) Rainfall (mm) 1 5.95 13 147.075 2 16.525 14 148.525 3 30.3 15 152.625 4 49.4 16 158.525 68.625 17 163.875 90.575 18 170.4 105.1 19 179.45 106.05 20 194.225 9 117.575 21 210.95 10 131.175 22 231.35 11 141.675 23 243.6 12 146.525 24 250 Transform this cumulative rainfall series from a local rain gauge into an incremental rainfall hyetograph. If this fell over a watershed with an area of 1 hectare, what was the volume of rainfall (m3) distributed over the watershed? 67 00

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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NOTE: FLUX Q FOR WEEK 2 A. -0.0998 cm/day B. -0.9098 cm/day C. -0.0899 cm/day D. -0.8099 cm/day
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An engineer’s transit was set up at a central station O. Four surrounding points A, B, C and D were observed. Angle AOB 63°25’, BOC 55°45’, COD, 29°15’ and DOA 31°10’. What is the most probable value (MPV) of angle BOC?a. 55°51’15” b. 49°30’ c. 100°38’45” d. 10°51’15” What is the MPV of COD? a. 29°08’45” b. 15°38’45’ c. 74°08’45” d. 29°21’15”
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Question: Use the Thiessen polygon method to find the mean areal precipitation for the area composed of a square and an equilateral triangular plot of side 2.5 km. Rainfall values (in cm) at the stations are as indicated.
solve problem 29 and 30
Load (N) Deflection (mm) 0 0 4.903034 0.000346 11.416539 0.000802 18.337648 0.001251 25.050375 0.001727 29.707962 0.002173 31.75 0.002634 29.888114 0.003094
Correct Answer: 3,503.24 N/m
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