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Rate Law from Concentration versus Time Data NO2(9) + CO(g) NO(g) + CO2(g) The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C. At a temperature below 225°C the following data were obtained: [NO2] (mol/L) Time (s) 0.560 5.00x102 0.547 1.25x103 0.528 1.88x103 0.513

Rate Law from Concentration versus Time Data NO2(9) + CO(g) NO(g) + CO2(g) The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C. At a temperature below 225°C the following data were obtained: [NO2] (mol/L) Time (s) 0.560 5.00x102 0.547 1.25x103 0.528 1.88x103 0.513

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section: Chapter Questions
Problem 78GQ
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Rate Law from Concentration versus Time Data NO2(9) + CO(g) NO(g) + CO2(g) The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C. At a temperature below 225°C the following data were obtained: [NO2] (mol/L) Time (s) 0.560 5.00x102 0.547 1.25x103 0.528 1.88x103 0.513 3.75x103 0.473 7.50x103 0.409 Which of the following expressions for the rate law (either differential or integrated) are completely consistent with the above experimental data. v d[NO]/dt = k[NO2]? v In[NO2] - In[NO2lo = -kt v K[CO][NO2] = -d[CO]/dt v 1/[NO2] = kt + 1/[NO2]o v -d[NO2]/dt = k[NO2]2 提交答案| Tries 0/5 Calculate the rate constant (k). Enter the numerical value and corresponding Units.
Transcribed Image Text:Rate Law from Concentration versus Time Data NO2(9) + CO(g) NO(g) + CO2(g) The rate of the above reaction depends only on the concentration of nitrogen dioxide at temperatures below 225°C. At a temperature below 225°C the following data were obtained: [NO2] (mol/L) Time (s) 0.560 5.00x102 0.547 1.25x103 0.528 1.88x103 0.513 3.75x103 0.473 7.50x103 0.409 Which of the following expressions for the rate law (either differential or integrated) are completely consistent with the above experimental data. v d[NO]/dt = k[NO2]? v In[NO2] - In[NO2lo = -kt v K[CO][NO2] = -d[CO]/dt v 1/[NO2] = kt + 1/[NO2]o v -d[NO2]/dt = k[NO2]2 提交答案| Tries 0/5 Calculate the rate constant (k). Enter the numerical value and corresponding Units.
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