Please answer exercise parts! Thank you! GOAL Apply the more general definition of torque.300 NHinge60.0°2.00 mHinge260 N150 N2.00 m(a) Top view of a door being pushed by a 300-N force. (b) The components of the 300-Nforce.PROBLEM (a) A man applies a force of F = 3.00 x 102 N at an angle of 60.0° to the doorof Figure (a), 2.00 m from well-oiled hinges. Find the torque on the door, choosing the positionof the hinges as the axis of rotation. (b) Suppose a wedge is placed 1.50 m from the hingeson the other side of the door. What minimum force must the wedge exert so that the forceapplied in part (a) won't open the door?STRATEGY Part (a) can be solved by substitution into the general torque equation. In part(b) the hinges, the wedge, and the applied force all exert torques on the door. The door doesn'topen, so the sum of these torques must be zero, a condition that can be used to find thewedge force.SOLUTION(A) Compute the torque due to the applied force exerted at 60.0°,TE = IFsin O- (2.00 m)(3.00 x 102 N) sin 60.0= (2.00 m)(2.60 x 102 N) = 5.20 x 102 N mSubstitute into the general torquequation.(B) Calculate the force exerted by the wedge on the other side of the door.Set the sum of the torques equalThinge * Twedge + TE=0to zero.The hinge force provides no0+ Fwadae(1.50 m) sin (-90.0") + 5.20 x 102 N- mtorque because it acts at the axis= 0(r = 0). The wedge force acts atan angle of -90.0", opposite theFwedge " 347 Nupward 260 N component.LEARN MOREREMARKS Notice that the angle from the position vector to the wedge force is -90'. This isbecause, starting at the position vector, it's necessary to go 90° clockwise (the negativeangular direction) to get to the force vector. Measuring the angle in this way automaticallysupplies the correct sign for the torque term and is consistent with the right-hand rule.Alternately, the magnitude of the torque can be found and the correct sign chosen based onphysical intuition. Figure (b) illustrates the fact that the component of the force perpendicularto the lever arm causes the torque.QUESTION To make the wedge more effective in keeping the door closed, should it beplaced closer to the hinge or to the doorknob?O closer to the hinge• closer to the doorknobPRACTICE ITUse the worked example above to help you solve this problem.(a) A man applies a force of F = 3.00 x 102 N at an angle of 60.0* to a door, x = 2.50 mfrom the hinges. Find the torque on the door, choosing the position of the hinges as theaxis of rotation.649.5v N mN-m(b) Suppose a wedge is placed 1.50 m from the hinges on the other side of the door.What minimum force must the wedge exert so that the force applied in part (a) won'topen the door?433EXERCISEHINTS: GETTING STARTED | I'M STUCKIA man ties one end of a strong rope 8.60 m long to the bumper of his truck, 0.587 m from theground, and the other end to a vertical tree trunk at a height of 2.90 m. He uses the truck tocreate a tension of 8.08 x 10 N in the rope. Compute the magnitude of the torque on the treedue to the tension in the rope, with the base of the tree acting as the reference point.N-m

Question

Please answer exercise parts! Thank you! GOAL Apply the more general definition of torque.300 NHinge60.0°2.00 mHinge260 N150 N2.00 m(a) Top view of a door being pushed by a 300-N force. (b) The components of the 300-Nforce.PROBLEM (a) A man applies a force of F = 3.00 x 102 N at an angle of 60.0° to the doorof Figure (a), 2.00 m from well-oiled hinges. Find the torque on the door, choosing the positionof the hinges as the axis of rotation. (b) Suppose a wedge is placed 1.50 m from the hingeson the other side of the door. What minimum force must the wedge exert so that the forceapplied in part (a) won't open the door?STRATEGY Part (a) can be solved by substitution into the general torque equation. In part(b) the hinges, the wedge, and the applied force all exert torques on the door. The door doesn'topen, so the sum of these torques must be zero, a condition that can be used to find thewedge force.SOLUTION(A) Compute the torque due to the applied force exerted at 60.0°,TE = IFsin O- (2.00 m)(3.00 x 102 N) sin 60.0= (2.00 m)(2.60 x 102 N) = 5.20 x 102 N mSubstitute into the general torquequation.(B) Calculate the force exerted by the wedge on the other side of the door.Set the sum of the torques equalThinge * Twedge + TE=0to zero.The hinge force provides no0+ Fwadae(1.50 m) sin (-90.0&#34;) + 5.20 x 102 N- mtorque because it acts at the axis= 0(r = 0). The wedge force acts atan angle of -90.0&#34;, opposite theFwedge &#34; 347 Nupward 260 N component.LEARN MOREREMARKS Notice that the angle from the position vector to the wedge force is -90'. This isbecause, starting at the position vector, it's necessary to go 90° clockwise (the negativeangular direction) to get to the force vector. Measuring the angle in this way automaticallysupplies the correct sign for the torque term and is consistent with the right-hand rule.Alternately, the magnitude of the torque can be found and the correct sign chosen based onphysical intuition. Figure (b) illustrates the fact that the component of the force perpendicularto the lever arm causes the torque.QUESTION To make the wedge more effective in keeping the door closed, should it beplaced closer to the hinge or to the doorknob?O closer to the hinge• closer to the doorknobPRACTICE ITUse the worked example above to help you solve this problem.(a) A man applies a force of F = 3.00 x 102 N at an angle of 60.0* to a door, x = 2.50 mfrom the hinges. Find the torque on the door, choosing the position of the hinges as theaxis of rotation.649.5v N mN-m(b) Suppose a wedge is placed 1.50 m from the hinges on the other side of the door.What minimum force must the wedge exert so that the force applied in part (a) won'topen the door?433EXERCISEHINTS: GETTING STARTED | I'M STUCKIA man ties one end of a strong rope 8.60 m long to the bumper of his truck, 0.587 m from theground, and the other end to a vertical tree trunk at a height of 2.90 m. He uses the truck tocreate a tension of 8.08 x 10 N in the rope. Compute the magnitude of the torque on the treedue to the tension in the rope, with the base of the tree acting as the reference point.N-m

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