Recall that the average speed between times t and t2 is calculated using y(tz) – y(t;) t2 - ti Vave We are given that y = 55t – 1.86. Evaluating at t = 1, we have y(1) = 55(1) – 1.86(1)² = 53.14. Thus, the average speed between times 1 and 1 + h is as follows. (1 + h) – y(1) Vave = (1 + h) – 1 [55(1 + h) – 1.86(1 + h)²] – 53.14 51.28h - h, h+0

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.6: Proportion And Variation
Problem 18E
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Recall that the average speed between times t and tz is calculated using
y(t2) – y(t,)
Vave =
t2 - t1
We are given that y = 55t – 1.862. Evaluating at t = 1, we have
y(1) = 55(1) – 1.86(1)2 = 53.14.
Thus, the average speed between times 1 and 1 + h is as follows.
y(1 + h) – y(1)
Vave =
(1 + h) - 1
[55(1 + h) – 1.86(1 + h)²] – 53.14
51.28h -
h
h, h+0
Transcribed Image Text:Recall that the average speed between times t and tz is calculated using y(t2) – y(t,) Vave = t2 - t1 We are given that y = 55t – 1.862. Evaluating at t = 1, we have y(1) = 55(1) – 1.86(1)2 = 53.14. Thus, the average speed between times 1 and 1 + h is as follows. y(1 + h) – y(1) Vave = (1 + h) - 1 [55(1 + h) – 1.86(1 + h)²] – 53.14 51.28h - h h, h+0
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