LESSON 16 SESSION 290A rectangular garden has a width of 90 feet. The perimeter of the gardenis 500 feet. What is the length of the garden?500 (2 x ) + ( 2A\40)158°= 20500-=26 +180080+2=6L00-0th of the garden isfeet.aninn the p1ces

given width w=90 ft , P=500perimeter P = 2l + 2w 500 = 2l +2×90500=2l+180500-180 =2l

Answered: rectangular garden has a width of 90…

rectangular garden has a width of 90 feet. The pe 500 feet. What is the length of the garden? 500 = (2 x €) + . 500-26+ 80 180 = 20 %3D

Trigonometry (MindTap Course List)

8th Edition

ISBN:9781305652224

Author:Charles P. McKeague, Mark D. Turner

Publisher:Charles P. McKeague, Mark D. Turner

Chapter2: Right Triangle Trigonometry

Section2.4: Applications

Problem 58PS: If the angle of elevation to the sun is 74.3 when a flagpole casts a shadow of 22.5 feet, what is...

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Question

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LESSON 16 SESSION 2
90
A rectangular garden has a width of 90 feet. The perimeter of the garden
is 500 feet. What is the length of the garden?
500 (2 x ) + ( 2
A\
40)
158°
= 20
500-=26 +
180
080
+2=6
L00-0
th of the garden is
feet.
anin
n the p
1ces

Expert Solution

Step 1

$g i v e n w i d t h w = 90 f t, P = 500 p e r i m e t e r P = 2 l + 2 w 500 = 2 l + 2 \times 90 500 = 2 l + 180 500 - 180 = 2 l$

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