TC is a tangent to a circle at C and BA produced meets this tangent at T. Show that triangles TCA and TBC are similar and hence prove that TC? = TA x TB. %3D
TC is a tangent to a circle at C and BA produced meets this tangent at T. Show that triangles TCA and TBC are similar and hence prove that TC? = TA x TB. %3D
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter6: Circles
Section6.4: Some Constructions And Inequalities For The Circle
Problem 34E: A tangent ET is constructed to circle Q from external point E. Which angle and which side of...
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