Recursive Procedure fact(3) fact: $sp, $sp,8 $ra,4 ($sp) $a0,0 ($sp) $t0,$a0,1 $t0,$zero,L1 $v0,$zero,1 sub SW SW slt beg add add Śsp. Śsp 8
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- In Python, 1. Elements in a Quene or Stack are removed in the order in which they were added. 2. Elements in a Quene or Stack are removed in reverse order: the most recently added item is the first to be removed. Choose the appropriate choice56. What is the stack pop operation? Group of answer choices The pop operation reads and discards the next character from the input stream. An istream processes characters in the order they are received. The pop operation reads and discards the next character from the input stream. A stack processes characters in the LIFO fashion. The pop operation reads and discards the first character from the input stream. A stack processes characters in the LIFO fashion. The pop operation reads and discards the last character from the input stream. An istream processes characters in the order they are received. The stack top operation reads and discards the next character from the input stream. An istream processes characters in the order they are received.Knowledge of Stack Data Structure is a must. Create a stack data structure that can hold at most 10 items. Operations: Push, adds a new item on top of the stack. Pop, removes the item on top of the stack Top, returns the top item on top of the stack To add item on top of the stack, enter PUSH followed by the value ex. PUSH 20 To remove the item on top of the stack, enter POP ex. POP To print the value on top of the stack, enter TOP and it will print the top value and exit the loop. ex. TOP Rest assured that the input will not generate IndexOutOfBoundsException Input 1. Operation e.g. PUSH 10, POP, TOP Description PUSH operation always comes first. Number of POP operations is equal to number of PUSH operations TOP will be the last. Sample PUSH·10 PUSH·20 POP TOP Output Enter·PUSH·N·to·add·value,·N·is·int·value Enter·POP·to·remove·value Enter·TOP·to·print·final·result: PUSH·10 PUSH·20 POP TOP 10
- 54. What is the difference between the top and pop operations of a stack? Group of answer choices The top operation removes the top item of the stack. The pop operation returns a reference to the top item on the stack and remove it. The top operation removes the top item of the stack. The pop operation returns a reference to the top item on the stack without removing it. The pop operation removes the top item of the stack. The top operation returns a reference to the top item on the stack without removing it. The pop and top operations are doing the same thing which removes the top item of the stack. The pop operation removes the top item of the stack. The top operation returns a reference to the top item on the stack and remove it.Postfix using StacksThe rules to convert an infix expression into an equivalent postfix expression are as follows: Suppose infx represents the expression and pfx represents the postfix expression. The rules to convert infx into pfx are as follows: 1. Initialize pfx to an empty expression and also initialize the stack.2. Get the next symbol, sym, from infx. a. if sym is an operand, append sym to pfx b. if sym is (. push sym into the stack. c. if dym is ). pop snd append all the symbols from the stack until the most recent left parenthesis. Pop and discard the left parentheses. d. If sym is an operator: i. Pop and append all of the operators from the stack to pfx that are above the most recent left parenthesis and have precededence greater than or equal to sym ii. Push sym onto the stack. 3. After processing infx, some operators might be left in the stack. Pop and append to pfx everything from the stack. In this program, you will…Q: Write the code in c++ of Stack By Link List and Perform MultipleTask which are given below. Add all the given tasks in the code 1. Push value in stack2. Check that Stack is Empty or Not.3. POP values From Stack.4. Search any values from stack.5. Update any value from stack. NOTE: STACK BY LINKLIST
- Consider the following statements: stackType<int> stack; int x; Suppose that the input is: 14 53 34 32 13 5 -999 Show what is output by the following segment of code: cin >> x; while (x != -999) { if (x % 2 == 0) { if (!stack.isFullStack()) stack.push(x); } else cout << "x = " << x << endl; cin >> x; } cout << "Stack Elements: "; while (!stack.isEmptyStack()) { cout << " " << stack.top(); stack.pop(); } cout << endl;Q: Write the code in c++ of Stack By Link List and Perform MultipleTask which are given below. 1. Push value in stack2. Check that Stack is Empty or Not.3. POP values From Stack.4. Search any values from stack.5. Update any value from stack. NOTE: STACK BY LINKLIST// the language is c++, please code with common for better understanding, and after your code finished take a screenshot of the execution. Write a C++ program to simulate a stack using an array. You should create an index (the stack pointer) to point into the stack. Initialize it to 0. The stack should grow to location [1], [2], [3], etc. Write a "push (int)" function to push an int onto the top of the stack. Also, write an "int pop" instruction to pop the data that is stored on the top of the stack. The pop instruction must return the popped data. The push and pop instructions should increment and decrement the stack pointer appropriately. Your source should contain calls to your functions demonstrating that it works. Note, that you should do several pushes and several pops to show that data is correctly stored on the stack. You can do this by showing sample runs. Cut and paste the results of the runs into a separate document
- Given the following infix expression: (A + B) / (C + (D - E)) Convert from infix to postfix using stack. You must show all states of the stack during the conversion process. Infix expression STACK (head to the left) Output (A + B) / (C + (D - E))PLease help fix my Python code, tell me also what's wrong ... def hasDuplicateParanthesis(expression): If not expression or len(expression) <= 3 : return False #empty stack of characters needed first Stack = deque () #traversing through the input expression for c in Expression : #if character is not a closing paranthesis If C != ‘)’: Stack.append(c) # if character having closed paranthesis else If stack[-1] == ‘(‘ : Return True #pop till ‘(‘ is found While stack[-1] != ‘(‘: stack.pop() Stack.pop() Return False if —name— == ‘__main__’: expression = ‘((X+Y))’ # let consider this a valid expression if HasDuplicateParanthesis(expression) Print (‘the given expression has duplicate paranthesis’) else: print (‘The expression does…C++ Programming, TOPIC: Stack queue and dequeImprove the error code below. See attached photo for the instructions and some of the errors. main.cpp #include <iostream> #include <cstring> #include "sllstack.h" using namespace std; int main(int argc, char** argv) { SLLStack* stack = new SLLStack(); int test; string str; cin >> test; switch (test) { case 0: bool ispar(string x); string x=str; stack<char> s; for(int i=0;i<x.length();++i) { if(x[i]=='(' or x[i]=='{' or x[i]=='[') s.push(x[i]); else if (x[i]==')' and !s.empty()) { if(s.top()!='(') return false; s.pop(); } else if(x[i]=='}' and s.empty()!=1) { if(s.top()!='{') return false; s.pop(); } else…