Redo the third problem of the Prelaboratory Assignment, substituting NaIO3 (sodium iodate) for NaOCl. The new reaction yields I2 as the only product containing a halogen. 3.A 10.0-mL sample of aqueous NaOCI is treated with excess KI in an acidic solution. The quantityof iodine that is liberated is such that 28.02 mL of 0.0250 M Na₂S₂O3 solution must be added tocause the disappearance of the dark blue color due to the starch indicator. What is the molarity ofthe solution of NaOCI?# of moles of Na2S203 = M*V= 0.0250 M * 28.02mL = 0.7005mmol2. According to the balanced equation2 moles of $203 2- reacts with 1 mole of CIO-so 0.7005mmol of $203 2- reacts with 0.7005 mmol * 1/2 = 0.35025 mmol of CIO-# of moles of NaOCI= 0.35025 mmolvolume = 10mlMolarity of NaOCI=0.35025 mmol/ 10.0ml = 0.0350 M The Strength of a Laundry BleachPrelaboratory AssignmentWrite the balanced equations for the following oxidation-reduction reactions that you willencounter in this experiment:The reduction of CIO by I in acidic solution1.2.a.C1012H₂0+21Iz+CI+H₂Ob.The reduction of I₂ by S₂O3 in acidic solution2-1₂+ 25 ₂0²² → 21+ SadWhat conversion factor will enable you to calculate the number of moles of ClO ions from thenumber of moles of S₂O3 ions used in the titration?2-2 moles of $₂03 = 1 mole ofCIÓ

Reduction of ClO- by I- in an acidic medium ClO- + 2I- + 2H+ →I2 + Cl- + H2O Reduction of I2 by…

Answered: A 10.0-ml sample of aqueous NaOCI is…

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 20Q

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Redo the third problem of the Prelaboratory Assignment, substituting NaIO3 (sodium iodate) for NaOCl. The new reaction yields I2 as the only product containing a halogen.

3.
A 10.0-mL sample of aqueous NaOCI is treated with excess KI in an acidic solution. The quantity
of iodine that is liberated is such that 28.02 mL of 0.0250 M Na₂S₂O3 solution must be added to
cause the disappearance of the dark blue color due to the starch indicator. What is the molarity of
the solution of NaOCI?
# of moles of Na2S203 = M*V= 0.0250 M * 28.02mL = 0.7005mmol
2. According to the balanced equation
2 moles of $203 2- reacts with 1 mole of CIO-
so 0.7005mmol of $203 2- reacts with 0.7005 mmol * 1/2 = 0.35025 mmol of CIO-
# of moles of NaOCI= 0.35025 mmol
volume = 10ml
Molarity of NaOCI=0.35025 mmol/ 10.0ml = 0.0350 M

The Strength of a Laundry Bleach
Prelaboratory Assignment
Write the balanced equations for the following oxidation-reduction reactions that you will
encounter in this experiment:
The reduction of CIO by I in acidic solution
1.
2.
a.
C1012H₂0+21Iz+CI+H₂O
b.
The reduction of I₂ by S₂O3 in acidic solution
2-
1₂+ 25 ₂0²² → 21+ Sad
What conversion factor will enable you to calculate the number of moles of ClO ions from the
number of moles of S₂O3 ions used in the titration?
2-
2 moles of $₂03 = 1 mole of
CIÓ

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