Chlorine gas was first prepared in 1774 by C. W. Scheele by oxidizing sodium chloride with manganese(IV) oxide. The reaction is NaCl ( a q ) + H 2 SO 4 ( a q ) + MnO 2 ( s ) → Na 2 SO 4 ( a q ) + MnCl 2 ( a q ) + H 2 O ( l ) + Cl 2 ( g ) Balance this equation.

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Interpretation Introduction Interpretation: The chemical reaction for the preparation of chlorine by the reaction of sodium chloride with manganese ( IV ) oxide is given. The balanced equation for the given chemical reaction is to be stated. Concept introduction: According to law of conservation of mass the mass of each and every species present in a chemical reaction must be balanced. The number of electrons gained and lost in a chemical reaction must also be equal to maintain the overall charge on both sides of the chemical reaction. To determine: The balanced chemical equation for the given reaction. Explanation The given equation contains 4 chlorine atoms in the product side, while there is only 1 chlorine in reactant side. So, balance the chlorine by multiplying NaCl with the coefficient 4 . 4NaCl ( aq ) +H 2 SO 4 ( aq ) +MnO 2 ( s ) → 2Na 2 SO 4 ( aq ) +MnCl 2 ( aq ) +Cl 2 ( g ) +H 2 O ( l ) Now the number of sodium atoms become 2 in the product side while it is 4 in reactant side

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Answer 1

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Chemistry: An Atoms First Approach

2nd Edition

Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

ISBN: 9781305079243

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BuyFind

Chemistry: An Atoms First Approach

2nd Edition

Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

ISBN: 9781305079243

Solutions

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Section

Answer 3

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Answer 4

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Answer 5

Interpretation Introduction

Interpretation:

The chemical reaction for the preparation of chlorine by the reaction of sodium chloride with manganese (IV) oxide is given. The balanced equation for the given chemical reaction is to be stated.

Concept introduction:

According to law of conservation of mass the mass of each and every species present in a chemical reaction must be balanced. The number of electrons gained and lost in a chemical reaction must also be equal to maintain the overall charge on both sides of the chemical reaction.

To determine: The balanced chemical equation for the given reaction.

Explanation of Solution

The given equation contains 4 chlorine atoms in the product side, while there is only 1 chlorine in reactant side. So, balance the chlorine by multiplying NaCl with the coefficient 4 .

4NaCl(aq)+H2SO4(aq)+MnO2(s)→2Na2SO4(aq)+MnCl2(aq)+Cl2(g)+H2O(l)

Now the number of sodium atoms become 2 in the product side while it is 4 in reactant side

Chlorine gas was first prepared in 1774 by C. W. Scheele by oxidizing sodium chloride with manganese(IV) oxide. The reaction is NaCl ( a q ) + H 2 SO 4 ( a q ) + MnO 2 ( s ) → Na 2 SO 4 ( a q ) + MnCl 2 ( a q ) + H 2 O ( l ) + Cl 2 ( g ) Balance this equation.

Chemistry: An Atoms First Approach

Solutions

Chemistry: An Atoms First Approach

Chlorine gas was first prepared in 1774 by C. W. Scheele by oxidizing sodium chloride with manganese(IV) oxide. The reaction is

NaCl ( a q ) + H 2 SO 4 ( a q ) + MnO 2 ( s ) → Na 2 SO 4 ( a q ) + MnCl 2 ( a q ) + H 2 O ( l ) + Cl 2 ( g )

Balance this equation.

Explanation of Solution

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