Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. TInterval (13.046,22.15) X= 17.598 Sx = 16.01712719 n= 50 a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly. 13.05 Mbps < u< 22.15 Mbps (Round to two decimal places as needed.) b. Identify the best point estimate of u and the margin of error. The point estimate of u is (Round to two decimal places as needed.) Mbps. The margin of error is E = Mbps. (Round to two decimal places as needed.) c. In constructing the confidence interval estimate of u, why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution? O A. Because the sample is a random sample, the distribution of sample means can be treated as a normal distribution. O B. Because the sample standard deviation OC. Because the population standard deviation is known, the normal distribution can be used to construct the confidence interval. known, the normal distribution can be used to construct the confidence interval.

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Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below.
TInterval
(13.046,22.15)
X= 17.598
Sx = 16.01712719
n= 50
a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly.
13.05 Mbps < u< 22.15 Mbps
(Round to two decimal places as needed.)
b. Identify the best point estimate of u and the margin of error.
The point estimate of u is
(Round to two decimal places as needed.)
Mbps.
The margin of error is E = Mbps.
(Round to two decimal places as needed.)
c. In constructing the confidence interval estimate of u, why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution?
O A. Because the sample is a random sample, the distribution of sample means can be treated as a normal distribution.
O B. Because the sample standard deviation
OC. Because the population standard deviation is known, the normal distribution can be used to construct the confidence interval.
known, the normal distribution can be used to construct the confidence interval.
Transcribed Image Text:Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. TInterval (13.046,22.15) X= 17.598 Sx = 16.01712719 n= 50 a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly. 13.05 Mbps < u< 22.15 Mbps (Round to two decimal places as needed.) b. Identify the best point estimate of u and the margin of error. The point estimate of u is (Round to two decimal places as needed.) Mbps. The margin of error is E = Mbps. (Round to two decimal places as needed.) c. In constructing the confidence interval estimate of u, why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution? O A. Because the sample is a random sample, the distribution of sample means can be treated as a normal distribution. O B. Because the sample standard deviation OC. Because the population standard deviation is known, the normal distribution can be used to construct the confidence interval. known, the normal distribution can be used to construct the confidence interval.
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