[References] When 1 mole of toluene is vaporized at a constant pressure of 1.00 atm and at its boiling point of 383.8 K, 33.18 kJ of energy (heat) is absorbed and the volume change is +31.50 L. What are AE and AH for this process? AE = kJ ΔΗ- kJ

[References] When 1 mole of toluene is vaporized at a constant pressure of 1.00 atm and at its boiling point of 383.8 K, 33.18 kJ of energy (heat) is absorbed and the volume change is +31.50 L. What are AE and AH for this process? AE = kJ ΔΗ- kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter10: Liquids And Solids

Section: Chapter Questions

Problem 141CP: When I mole of benzene is vaporized at a constant pressure of 1.00 atm and at its boiling point of...

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[References]
When 1 mole of toluene is vaporized at a constant pressure of 1.00 atm and at its boiling point of 383.8 K, 33.18 kJ of energy (heat) is absorbed and the
volume change is +31.50 L. What are AE and AH for this process?
AE =
kJ
AH =
kJ
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