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Calculate the amount of energy in kilojoules needed to change 243 g of water ice at –10 °C to steam at 125 °C. The following constants may be useful: • Cm (ice) = 36.57 J mol¬1 °C-1 Cm (water) = 75.40 J mol¬1 °C-1 • Cm (steam) = 36.04 J mol-1 °C-1 Afus H = +6.01 kJ mol¬! Avap H = +40.67 kJ mol¬1 Express your answer with the appropriate units. HA ? Value Units Submit Request Answer

Calculate the amount of energy in kilojoules needed to change 243 g of water ice at –10 °C to steam at 125 °C. The following constants may be useful: • Cm (ice) = 36.57 J mol¬1 °C-1 Cm (water) = 75.40 J mol¬1 °C-1 • Cm (steam) = 36.04 J mol-1 °C-1 Afus H = +6.01 kJ mol¬! Avap H = +40.67 kJ mol¬1 Express your answer with the appropriate units. HA ? Value Units Submit Request Answer

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 51E: A sample of 0.562 g of carbon is burned in oxygen in a bomb calorimeter, producing carbon dioxide....
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Part B Calculate the amount of energy in kilojoules needed to change 243 g of water ice at –10 °C to steam at 125 °C. The following constants may be useful: Cm (ice) = 36.57 J mol-1 °C-1 Cm (water) = 75.40 J mol-1 °C-1 Cm (steam) = 36.04 J mol-1 °C-1 Afus H = +6.01 kJ mol¬1 Avap H = +40.67 kJ mol¬1 Express your answer with the appropriate units. HA Value Units Submit Request Answer
Transcribed Image Text:Part B Calculate the amount of energy in kilojoules needed to change 243 g of water ice at –10 °C to steam at 125 °C. The following constants may be useful: Cm (ice) = 36.57 J mol-1 °C-1 Cm (water) = 75.40 J mol-1 °C-1 Cm (steam) = 36.04 J mol-1 °C-1 Afus H = +6.01 kJ mol¬1 Avap H = +40.67 kJ mol¬1 Express your answer with the appropriate units. HA Value Units Submit Request Answer
Matter can change from one physical state (phase) to another without any change in chemical identity. Each change is characterized by a specific name, a APCH (enthalpy) value, and a ApcS (entropy) value. The energy involved in phase changes and temperature changes can be calculated by using the following equations. For a phase change (with no change in temperature) energy ApcH × n where ApcH is the enthalpy change for that transition and n is the number of moles of the substance. For a temperature change (with no change in phase) energy Cη x ΔTx n where Cm is the molar heat capacity, n is the number of moles, and AT is the temperature change in degrees Celsius.
Transcribed Image Text:Matter can change from one physical state (phase) to another without any change in chemical identity. Each change is characterized by a specific name, a APCH (enthalpy) value, and a ApcS (entropy) value. The energy involved in phase changes and temperature changes can be calculated by using the following equations. For a phase change (with no change in temperature) energy ApcH × n where ApcH is the enthalpy change for that transition and n is the number of moles of the substance. For a temperature change (with no change in phase) energy Cη x ΔTx n where Cm is the molar heat capacity, n is the number of moles, and AT is the temperature change in degrees Celsius.
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