Repeater Example Example 6.10 Compute the delay per mm of a repeated wire in a 65 nm process. Assume the wire is RW on a middle routing layer and has 2x width, spacing, and height, so its resistance is 200 2/mm and capacitance is 0.2 pF/mm. The FO4 inverter delay is 15 ps. Also find the repeater spacing and driver size to achieve this delay and the energy per bit. SOLUTION: Using EQ (6.29), the delay is 'N =(2+ √2(1+ Pm))√RCRC = 1.67 √FO4 R_C_ p = 1.67√(15 ps) (200 2/mm)(0.2 pF/mm) = 41 ps/mm (6.32) This delay is achieved using a spacing of 0.45 mm between repeaters and an nMOS driver width of 18 um (180x unit size). The energy per bit is 0.4 pJ/mm. ③ Energy / length 1.87CwVDD2 14: Wires CMOS VLSI Design 4th Ed. 33 33

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There is an example of this in my book, im not sure how they got the final answer can you pleaseee explain the steps to get there. :)

Repeater Example
Example 6.10
Compute the delay per mm of a repeated wire in a 65 nm process. Assume the wire is
RW
on a middle routing layer and has 2x width, spacing, and height, so its resistance is 200
2/mm and capacitance is 0.2 pF/mm. The FO4 inverter delay is 15 ps. Also find the
repeater spacing and driver size to achieve this delay and the energy per bit.
SOLUTION: Using EQ (6.29), the delay is
'N
=(2+ √2(1+ Pm))√RCRC = 1.67 √FO4 R_C_
p = 1.67√(15 ps) (200 2/mm)(0.2 pF/mm) = 41 ps/mm
(6.32)
This delay is achieved using a spacing of 0.45 mm between repeaters and an nMOS
driver width of 18 um (180x unit size). The energy per bit is 0.4 pJ/mm.
③ Energy / length 1.87CwVDD2
14: Wires
CMOS VLSI Design 4th Ed.
33
33
Transcribed Image Text:Repeater Example Example 6.10 Compute the delay per mm of a repeated wire in a 65 nm process. Assume the wire is RW on a middle routing layer and has 2x width, spacing, and height, so its resistance is 200 2/mm and capacitance is 0.2 pF/mm. The FO4 inverter delay is 15 ps. Also find the repeater spacing and driver size to achieve this delay and the energy per bit. SOLUTION: Using EQ (6.29), the delay is 'N =(2+ √2(1+ Pm))√RCRC = 1.67 √FO4 R_C_ p = 1.67√(15 ps) (200 2/mm)(0.2 pF/mm) = 41 ps/mm (6.32) This delay is achieved using a spacing of 0.45 mm between repeaters and an nMOS driver width of 18 um (180x unit size). The energy per bit is 0.4 pJ/mm. ③ Energy / length 1.87CwVDD2 14: Wires CMOS VLSI Design 4th Ed. 33 33
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