Sample QuestionRetention Teat ScoresAample of non-Engliah majora ata elected college wa ued ina atudy to see if thestudent retained more from reading - 19th century novel or by watching it in DVD form. Each student wa Bignedone novel to read and a different one to watch, and then they were given a 20-point written quiz on each novel. Thetest results are ahoven below. At a= 0.01. can it be concluded that the book acores are higher than the DVD sores?Assume rhe variahle are normanily dieertbuted.gbaxCOhKa0S18zQQvuJZZ0CtHs.. QBook84 s688 92908090758090DVD85728080707590797793(Senn nta to Exce(-) Statu the hypothuaua nd iduntify th claim with the correct hypothwaa.(b) Find th P-value.(e) Make the decinion.(d) Summarize the reaulta.(a) State the hypotheses and identify the claim with the correct hypothesis.The null hypothesis H, is the statement that the difference between the matched pairs is zero. This is equivalent to un = 0.The alternative hypothesis H, is the statement that the difference between the matched pairs is not zero. Since we are interested to see if thereading quiz scores are higher than the DVD quiz scores, the differences must be greater than zero. This is equivalent to un0.The problem asks if it can "be concluded that the book scores are higher than the DVD scores." Hence, the claim is the alternative hypothesis(b) Find the P-value.The TI-83 Plus/TI-84 Plus graphing calculators do not provide a t test for the difference between means for dependent samples. However, thedifferences between the paired data in two lists can be calculated in a third list and then the single sample t test can be applied on that thirdlist of data.L1L2L3EDIT CALC TESTS90851: Z-Test...2: T-Test..80729080103: 2-SampZTest...4: 2-SampTTest...5: 1-PropZTest...6: 2-PropZTest...7Į ZInterval...7580-580701090758480L3 (7)- 4T-TestInpt: DataStatsList: L,Freq: 1u: + H HoCalculate DrawEnter the book scores in the list L1 and DVD scores data in the list L2. Move the cursor to the top of the L3 column so that L3 is highlighted.Type L1 - L2, then press ENTER.Then enter in the appropriate fields in the calculator.4, = 0, List = L3, Freq = 1, right-tailed test.Press the following keystrokes into either the TI-83 Plus or the TI-84 Plus calculator.STAT OO20ENTER) OO O 2and 3O MAPHA 100D ENTERO ENTER)t = 4.367236588p =9.0216862E-4x =7.4Your screen should display the following (or very similar) result.T-Testu 0t = 4.367236588Sx =5.3582750132 = 10p = 9.0216862E-4x = 7.4The P-value is 0.0009 rounded to 4 decimal places.Sx = 5.358275013(c) Make the decision.Hence, the null hypothesis is rejected as the P-value is less than a= 0.01.n = 10(d) Summarize the results.Since the null hypothesis was rejected, there is enough evidence to support the claim.The P-value is 0.0009 rounded to 4 decimal places. Retention Test Scores A sample of non-English majors at a selected college was used in a study to see if the student retainedmore from reading a 19"-century novel or by watching it in DVD form. Each student was assigned one novel to read and adifferent one to watch, and then they were given a 20-point written quiz on each novel. The test results are shown below. Ata = 0.05, can it be concluded that the book scores are higher than the DVD scores? Assume the variables are normally distributed.Вook9080907580908486DVD8572808070758079Send data to ExcelPart: 0 / 4Part 1 of 4(a) State the hypotheses and identify the claim with the correct hypothesis.H.:|(Choose one)H:(Choose one)This hypothesis test is a (Choose one) Vtest.

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Sample QuestionRetention Teat ScoresAample of non-Engliah majora ata elected college wa ued ina atudy to see if thestudent retained more from reading - 19th century novel or by watching it in DVD form. Each student wa Bignedone novel to read and a different one to watch, and then they were given a 20-point written quiz on each novel. Thetest results are ahoven below. At a= 0.01. can it be concluded that the book acores are higher than the DVD sores?Assume rhe variahle are normanily dieertbuted.gbaxCOhKa0S18zQQvuJZZ0CtHs.. QBook84 s688 92908090758090DVD85728080707590797793(Senn nta to Exce(-) Statu the hypothuaua nd iduntify th claim with the correct hypothwaa.(b) Find th P-value.(e) Make the decinion.(d) Summarize the reaulta.(a) State the hypotheses and identify the claim with the correct hypothesis.The null hypothesis H, is the statement that the difference between the matched pairs is zero. This is equivalent to un = 0.The alternative hypothesis H, is the statement that the difference between the matched pairs is not zero. Since we are interested to see if thereading quiz scores are higher than the DVD quiz scores, the differences must be greater than zero. This is equivalent to un>0.The problem asks if it can &#34;be concluded that the book scores are higher than the DVD scores.&#34; Hence, the claim is the alternative hypothesis(b) Find the P-value.The TI-83 Plus/TI-84 Plus graphing calculators do not provide a t test for the difference between means for dependent samples. However, thedifferences between the paired data in two lists can be calculated in a third list and then the single sample t test can be applied on that thirdlist of data.L1L2L3EDIT CALC TESTS90851: Z-Test...2: T-Test..80729080103: 2-SampZTest...4: 2-SampTTest...5: 1-PropZTest...6: 2-PropZTest...7Į ZInterval...7580-580701090758480L3 (7)- 4T-TestInpt: DataStatsList: L,Freq: 1u: + H < H, > HoCalculate DrawEnter the book scores in the list L1 and DVD scores data in the list L2. Move the cursor to the top of the L3 column so that L3 is highlighted.Type L1 - L2, then press ENTER.Then enter in the appropriate fields in the calculator.4, = 0, List = L3, Freq = 1, right-tailed test.Press the following keystrokes into either the TI-83 Plus or the TI-84 Plus calculator.STAT OO20ENTER) OO O 2and 3O MAPHA 100D ENTERO ENTER)t = 4.367236588p =9.0216862E-4x =7.4Your screen should display the following (or very similar) result.T-Testu >0t = 4.367236588Sx =5.3582750132 = 10p = 9.0216862E-4x = 7.4The P-value is 0.0009 rounded to 4 decimal places.Sx = 5.358275013(c) Make the decision.Hence, the null hypothesis is rejected as the P-value is less than a= 0.01.n = 10(d) Summarize the results.Since the null hypothesis was rejected, there is enough evidence to support the claim.The P-value is 0.0009 rounded to 4 decimal places. Retention Test Scores A sample of non-English majors at a selected college was used in a study to see if the student retainedmore from reading a 19&#34;-century novel or by watching it in DVD form. Each student was assigned one novel to read and adifferent one to watch, and then they were given a 20-point written quiz on each novel. The test results are shown below. Ata = 0.05, can it be concluded that the book scores are higher than the DVD scores? Assume the variables are normally distributed.Вook9080907580908486DVD8572808070758079Send data to ExcelPart: 0 / 4Part 1 of 4(a) State the hypotheses and identify the claim with the correct hypothesis.H.:|(Choose one)H:(Choose one)This hypothesis test is a (Choose one) Vtest.

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A sample of non-English majors at a selected college was used in a study to see if the student…