Returns the area of the largest rectangle in . The area of a rectangle is defined by number of 1's that it contains.
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using this code(PYTHON):
def longest_chain(lst: list[int]) -> int:
i = 0
answer = []
while i < len(lst) and lst[i] == 1:
answer.append(lst[i])
i += 1
return sum(answer)
How do I solve these two questions
Step by step
Solved in 2 steps
- A4. Code to remove duplicate elements from ArrayList in java? Using Java 8 Stream.distinct() Approach Get the ArrayList with duplicate values. Create a new List from this ArrayList. Using Stream().distinct() method which return distinct object stream. convert this object stream into List /**.Write a Python code using the given function and conditions. Do not use Numpy. Use LinkedList Manipulation. Given function: def insert(self, newElement, index) Pre-condition: The list is not empty. Post-condition: This method inserts newElement at the given index of the list. If an element with the same key as newElement value already exists in the list, then it concludes the key already exists and does not insert the key. [You must also check the validity of the index].Need help only part 2. Thank you! In this assignment, you will create a Linked List data structure variant called a “Circular Linked List”. The Node structure is the same as discussed in the slides and defined as follows (we will use integers for data elements): public class Node { public int data; public Node next; } For the Circular Linked List, its class definition is as follows: public class CircularLinkedList { public int currentSize; public Node current; } In this Circular Linked List (CLL), each node has a reference to an existing next node. When Node elements are added to the CLL, the structure looks like a standard linked list with the last node’s next pointer always pointing to the first. In this way, there is no Node with a “next” pointer in the CLL that is ever pointing to null. For example, if a CLL has elements “5”, “3” and “4” and “current” is pointing to “3”, the CLL should look like: Key observations with this structure:…
- 1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…
- What is the biggest advantage of linked list over array? Group of answer choices Unlike array, linked list can dynamically grow and shrink With linked list, it is faster to access a specific element than with array Linked list is easier to implement than array Unlike array, linked list can only hold a fixed number of elementsWhich of the following statements are true? A. Appending of elements to a dynamic list takes constant time. B. Row-wise traversal of 2-dimensional arrays is commonly faster than column-wise traversal. C. Tranversing an array is faster than traversing a linked list with the same number of entries. D. Node lookup time in a balanced binary search tres is O(1).Create a class Student with the fields: name (a String) and gpa (a double). Create a linked list of Student objects, called students using the LinkedList class from java.util.Sort the linked list students “by length” of name (see Sect. 11.3 in textbook) using the sort method from class Collections.Sort the initial linked list students by gpa using the sort method from class Collections. Apply the toArray() method from class LinkedList to the initial linked list students and sort the obtained array “by length” of name using the sort method from class Arrays. After each sort, print the result.Do NOT use the sort method from the List interface (also available from a LinkedList).
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