Review | Constants An archer standing on a 15° slope shoots an arrow 20° above the horizontal, as shown in the figure (Figure 1) Part A How far down the slope does the arrow hit if it is shot with a speed of 50 m/s? Hint: There are several strategies to solve this problem. This hint discusses two different methods. Method 1: The arrow must land on the slope, so write y(x) of the slope as y= tan(phi)*x, where phi is angle of the slope and it must be negative. Note that you need to define a coordinate system, which you might assign the origin at the position of the archer, and +x is to the right in graphic. All angles must be with respect to the positive x direction. The slope angle in the picture does not conform to this requirement so you have to determine the slope angle from the information given. That is why you should write-phi for the angle of the slope. The distance down the slope is just the sqrt[(displacement in x)^2+(displacement in y)^2]. Strategy: write the usual kinematic equations for x(t) and y(t) with v0 and launch angle theta since both are given to you. Subtitute y(t) with the equation tan(phi)*x to get two equations for x as a function of t. From those two equations, solve for time of flight, t, of the arrow. Once t is known, you can solve for displacement in x from the usual kinematic equation x(t) and you obtain the displacement in y from the usual kinematic equation for the y-component. Figure 1 of 1 20° Method 2: If you use a rotated coordinate system, so that +x lies in the down direction of the slope, then x is the distance. However in this coordinate system, gravitational acceleration has both x and y components, so this method requires that you solve the kinematic equations for acceleration in both y and x 15° Determine and x and y components for gravitational acceleration, call them g_x and g_y. You should be able to use geometry to determine that g_x= g*sin(phi) and g_y=-g*cos(phi), where phi is the angle of the slope P Pearson Review | Constants uiSpiactITEN TA IIUMI UIE usuai NUEITIALIU EquaLIUIT A[LY aiu yuu UDlaii iE ulSpiauEITIENN ILI y inUTI LUIE An archer standing on a 15° slope shoots an arrow 20° above the horizontal, as shown in the figure (Figure 1) usual kinematic equation for the y-component. Method 2: If you use a rotated coordinate system, so that +x lies in the down direction of the slope, then x is the distance. However in this coordinate system, gravitational acceleration has both x and y components, so this method requires that you solve the kinematic equations for acceleration in both y and x Determine and x and y components for gravitational acceleration, call them g_x and g_y. You should be able to use geometry to determine that g_x= g*sin(phi) and g_y=-g*cos(phi), where phi is the angle of the slope Determine launch angle in the rotated coordinate system, call it theta' The kinematic equations are relatively straightforward because in this coordinate sytem the arrows initial and final y-position is zero. Also, the final v_y is the negative of the initial v_y, so computing the time of flight is similar to the basic projectile motion problems from last week. So t-2"v0*sin(theta')/g_y. Also you only need the displacement in x v_Ox*t+(1/2)g_x*t^2 Figure 1 of 1 V ΑΣφ 20° m Request Answer Submit 15° Provide Feedback Next Pearson

Question 20 A helicopter is heading S 43° E (i.e. direction angle of 313°) with an airspeed of 27 mph, and the wind is blowing S 13° E (i.e. direction angle of 283°) at 10 mph. Helicopter's speed Round all numbers in your answers below to 2 places after the decimal point. (a) Find the velocity vector that represents the true heading of the helicopter. Type your answer in component form, (where a and b represent some numbers). Velocity vector of helicopter's true heading: (b) Find the helicopter's speed relative to the ground (in mph). mph (c) Find the helicopter's drift angle, 8. (The drift angle is the number of degrees that the helicopter will end up flying off-course.) 8 = Submit Question degrees

Hi, I need help trying to figure out these questions. © Determining magnitude of axis vectorsGx, = 0 & Gy, = 47. Determine G.G=- Determining the non-zero component of an axis vectorE has a magnitude of 26 & Ey = 0. Determine the two possible values for Ex

A person going for a walk follows the path shown in the figure. The total tripconsists of four straight-line paths. Use the component method of vector addition to calculate the person's resultant displacement measured from the starting pointa) in unit vector notationb) magnitude and direction.