Review | Constants Block 1, of mass m1 = 6.90 kg , moves along a frictionless air track with speed vi = 17.0 m/s. It collides with block 2, of mass m2 = 53.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) Part C What is the change AK = Kfinal - Kinitial in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules. Figure 1 of 1 • View Available Hint(s) Before collision: m2 m AK = 938.348 J Submit Previous Answers After collision: X Incorrect; Try Again; 4 attempts remaining Provide Feedback Next > 國

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
Problem 9.4OQ: A 2-kg object moving to the right with a speed of 4 m/s makes a head-on, elastic collision with a...
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I Review | Constants
Block 1, of mass m1 = 6.90 kg , moves along a
frictionless air track with speed v1 = 17.0 m/s. It collides
with block 2, of mass m2 = 53.0 kg , which was initially at
rest. The blocks stick together after the collision. (Figure 1)
Part C
What is the change AK = Kfinal – Kinitial in the two-block system's kinetic energy due to the collision?
Express your answer numerically in joules.
Figure
1 of 1
• View Available Hint(s)
V ΑΣΦ
?
Before collision:
m2
m1
AK = 938.348
2
J
Submit
Previous Answers
After collision:
X Incorrect; Try Again; 4 attempts remaining
1
Provide Feedback
Next >
Transcribed Image Text:I Review | Constants Block 1, of mass m1 = 6.90 kg , moves along a frictionless air track with speed v1 = 17.0 m/s. It collides with block 2, of mass m2 = 53.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) Part C What is the change AK = Kfinal – Kinitial in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules. Figure 1 of 1 • View Available Hint(s) V ΑΣΦ ? Before collision: m2 m1 AK = 938.348 2 J Submit Previous Answers After collision: X Incorrect; Try Again; 4 attempts remaining 1 Provide Feedback Next >
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