Direction: Consider the circuit below and fill in values on the table. Use MESH ANALYSIS in solving. R1R2R3R4Cell 1 (ε1)Cell 1 (ε2)Cell 1 (ε3)Cell 1 (ε4)R (Ω)2068150.50.250.50.75V (V) 1831218I (A) P (W) R, = 20 NR3 = 8 N%3Dan = 0.5 NR, = 6 N%3DEz = 3.0 VEzi= 12 V13= 0.5 NE{= 18|v12= 0.25 NEE4 = 18 Vf R = 15 Ned4 = 0.75 )

Answered: Image /qna-images/answer/604008d4-2be4-456d-b6db-db353774d91f.jpg

Answered: Rq = 20 ) R3 = 8 2 a 1 = 0.5 N R2 = 6 N…

Rq = 20 ) R3 = 8 2 a 1 = 0.5 N R2 = 6 N E, = 3.0 V Ez= 12 V 13= 0.5 N E,'= 18|v 2 = 0.25 N. E4 = 18 V 1 R-15Ω e d 4 = 0.75 ) %3D

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter18: Resistive-inductive Parallel Circuits

Section: Chapter Questions

Problem 9PP: In an R-L parallel circuit, ET=240 volts, R=560 R = 560 2, and XL=330. Find reactive power.

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Question

Direction: Consider the circuit below and fill in values on the table. Use MESH ANALYSIS in solving.

	R₁	R₂	R₃	R₄	Cell 1 (ε₁)	Cell 1 (ε₂)	Cell 1 (ε₃)	Cell 1 (ε₄)
R (Ω)	20	6	8	15	0.5	0.25	0.5	0.75
V (V)					18	3	12	18
I (A)
P (W)

R, = 20 N
R3 = 8 N
%3D
a
n = 0.5 N
R, = 6 N
%3D
Ez = 3.0 V
Ezi= 12 V
13= 0.5 N
E{= 18|v
12= 0.25 NE
E4 = 18 V
f R = 15 N
e
d
4 = 0.75 )

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